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Full Discussion: Echo working funny
Top Forums Shell Programming and Scripting Echo working funny Post 302327992 by hemtar on Tuesday 23rd of June 2009 06:41:12 AM
Old 06-23-2009
Quote:
Originally Posted by methyl
This actually unquotes the variable!
Code:
echo "123 "$string1" 123"

Can you post the whole script and state you Operating System and Shell?
hehe, yes! It does unquote the variable, because of that I put a pipe after the AWK loop like this:

Code:
        word_count++
            
        }
    }' | tr "\n" " ")

This worked fine!

HP-UX, KSH. The script is... too long to be posted! hehehe

Thank you very much anyway Smilie[COLOR="#738fbf"]

---------- Post updated at 05:41 AM ---------- Previous update was at 05:36 AM ----------

Quote:
Originally Posted by Franklin52
Use printf in your awk code instead of a print statement, replace this:

Code:
print $word_count

with:

Code:
printf "%s " $word_count


Didn't work, got this message in return:

Code:
awk: There are not enough parameters in printf statement %s sudo.
 The input line number is 1.
 The source line number is 7.

Trying to find the solution... this looks fancier than pipe the exit to tr statement Smilie

Regards

Last edited by hemtar; 06-23-2009 at 07:42 AM.. Reason: (quotation mistake)
 

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