Sponsored Content
Top Forums Shell Programming and Scripting control is not going inside the awk ? Post 302327601 by Anteus on Monday 22nd of June 2009 08:14:48 AM
Old 06-22-2009
Quote:
Originally Posted by vgersh99
Here's something to start with!
I never knew to type

dablu dablu dablu dot google dot kom..

thanks for showing me a start a decade back Smilie

regards
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Trim inside awk

Hi all, I am using qwk to parse the logfile. The code like awk ' { if($0 > " ") { MSISDN=substr($0,1,10) HOUR=substr($0,11,6); ID_SA_SOURCE=substr($0,17,18); ID_SA_DEST=substr($0,35,18); ... (3 Replies)
Discussion started by: subin_bala
3 Replies

2. Shell Programming and Scripting

Using variable inside awk

I am trying to print the lines with pattern and my pattern is set to a variable express awk '/$express/{where=NR;print}' test2.log I am not getting any data even though i have the data with the pattern. Can seomeone correct me with the awk command above? (20 Replies)
Discussion started by: rdhanek
20 Replies

3. UNIX for Dummies Questions & Answers

Awk inside Awk expression

Hi, It can be used awk inside other Awk?. I need to get another text processing while other text process. Thank you. (2 Replies)
Discussion started by: pepeli30
2 Replies

4. Shell Programming and Scripting

awk inside another awk statement

hi all, i have two files 1) a.txt one two three 2) abc "one" = 10 pqr "three" = 20 345 "two" = 0 this is what i want in third file (3 Replies)
Discussion started by: shishirkotkar
3 Replies

5. Shell Programming and Scripting

help: Awk to control number of characters per line

Hello all, I have the following problem: My input is two sorted files: file1 >1_19_130_F3 T01220131330230213311013000000110000 >1_23_69_F3 T01200211300200200010000001000000 >1_24_124_F3 T010203113002002111111200002010 file2 >1_19_130_F3 24 18 9 18 23 4 11 4 5 9 5 8 15 20 4 4 7 4... (9 Replies)
Discussion started by: DerSeb
9 Replies

6. UNIX for Dummies Questions & Answers

awk NR==FNR output control

Hi Guys, I have two files: f1: A B C D E F G H f2: A X Y Z f1 has 48000 lines, and f2 has 68. I have been matching f1 $3 to f2 $1, and getting f3: A A B C D E F G I would like f3 too look like this: A X Y Z A B C D E F G (2 Replies)
Discussion started by: heecha
2 Replies

7. Shell Programming and Scripting

HELP with AWK one-liner. Need to employ an If condition inside AWK to check for array variable ?

Hello experts, I'm stuck with this script for three days now. Here's what i need. I need to split a large delimited (,) file into 2 files based on the value present in the last field. Samp: Something.csv bca,adc,asdf,123,12C bca,adc,asdf,123,13C def,adc,asdf,123,12A I need this split... (6 Replies)
Discussion started by: shell_boy23
6 Replies

8. Shell Programming and Scripting

Split using AWK - out file name control

Hi Gurus, I am using following code to split a big file into pieces. awk '!((NR-1)%ln){close(f);f=name i++}{print>f}' i=1 name=my_file ln=25000 main_file The output that is produces is something like this - my_file2 my_file1 my_file4 my_file3 my_file5 my_file7 my_file6 my_file9... (3 Replies)
Discussion started by: mukesh.lalwani
3 Replies

9. Shell Programming and Scripting

Passing awk variable argument to a script which is being called inside awk

consider the script below sh /opt/hqe/hqapi1-client-5.0.0/bin/hqapi.sh alert list --host=localhost --port=7443 --user=hqadmin --password=hqadmin --secure=true >/tmp/alerts.xml awk -F'' '{for(i=1;i<=NF;i++){ if($i=="Alert id") { if(id!="") if(dt!=""){ cmd="sh someScript.sh... (2 Replies)
Discussion started by: vivek d r
2 Replies

10. UNIX for Dummies Questions & Answers

sed inside awk

What I want to do is delete everything upto the last underscore (_) in column 2. awk '{ $2=$(echo $2 | sed 's/.*_//'); print $0}' Sed works fine if I echo the string into it, this doesnt work inside awk. What am I doing wrong? Similarly, how do I store the substring starting with a... (4 Replies)
Discussion started by: senhia83
4 Replies
CHDIST(1)																 CHDIST(1)

NAME
chdist - script to easily play with several distributions SYNOPSIS
chdist [options] [command] [command parameters] DESCRIPTION
chdist is a rewrite of what used to be known as 'MultiDistroTools' (or mdt). Its use is to create 'APT trees' for several distributions, making it easy to query the status of packages in other distribution without using chroots, for instance. OPTIONS
-h, --help Provide a usage message. -d, --data-dir DIR Choose data directory (default: $HOME/.chdist/). -a, --arch ARCH Choose architecture (default: `dpkg --print-architecture`). --version Display version information. COMMANDS
create DIST [URL RELEASE SECTIONS] Prepare a new tree named DIST apt-get DIST <update|source|...> Run apt-get inside DIST apt-cache DIST <show|showsrc|...> Run apt-cache inside DIST apt-rdepends DIST [...] Run apt-rdepends inside DIST src2bin DIST SRCPKG List binary packages for SRCPKG in DIST bin2src DIST BINPKG List source package for BINPKG in DIST compare-packages DIST1 DIST2 [DIST3, ...] compare-bin-packages DIST1 DIST2 [DIST3, ...] List versions of packages in several DISTributions compare-versions DIST1 DIST2 compare-bin-versions DIST1 DIST2 Same as compare-packages/compare-bin-packages, but also runs dpkg --compare-versions and display where the package is newer. compare-src-bin-packages DIST Compare sources and binaries for DIST compare-src-bin-versions DIST Same as compare-src-bin-packages, but also run dpkg --compare-versions and display where the package is newer grep-dctrl-packages DIST [...] Run grep-dctrl on *_Packages inside DIST grep-dctrl-sources DIST [...] Run grep-dctrl on *_Sources inside DIST list List available DISTs COPYRIGHT
This program is copyright 2007 by Lucas Nussbaum and Luk Claes. This program comes with ABSOLUTELY NO WARRANTY. It is licensed under the terms of the GPL, either version 2 of the License, or (at your option) any later version. Debian Utilities 2013-12-23 CHDIST(1)
All times are GMT -4. The time now is 04:59 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy