06-21-2009
grep, awk will do the job for you.
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hi,
how would i extract a range of lines in a file by using the line number? ex: file contains:
1 title
2 i want
3 this part
4 to be taken out
5 from this file
6 and sent to
7 another file
8 not needed
9 end of file
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Hi
I want to extract certain text between two line numbers like
23234234324 and
54446655567567
How do I do this with a simple sed or awk command?
Thank you.
---------- Post updated at 06:16 PM ---------- Previous update was at 05:55 PM ----------
found it:
sed -n '#1,#2p'... (1 Reply)
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Dear all,
Greetings.
I would like to ask for your help to extract lines with specific words in addition 2 lines before and after these lines by using awk or sed.
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1 ak1 abc1.0
1 ak2 abc1.0
1 ak3 abc1.0
1 ak4 abc1.0
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Data file example
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ZGREP(1) General Commands Manual ZGREP(1)
NAME
zgrep - search possibly compressed files for a regular expression
SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename...
DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code:
(-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the
standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep.
If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.
EXIT CODE
2 - An option that is not supported was specified.
AUTHOR
Charles Levert (charles@comm.polymtl.ca)
SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)
ZGREP(1)