Say I have (in psuedocode)
For i=1 to 10
tar cvfb /... 5*i /junk(i)
end
What I mean is that I want each successive for loop to have the block size parameter be 5 times the current counter. This isn't my actual code, just a stupid example...So the question is how do I descrive that parameter... (2 Replies)
Hi,
I have one shell script which use two parameter however one of its parameter have space in between.
eg.
a.sh 20110114 b c d
here b c d is one parameter
I used 'b c d' but its not giving correct result.
Also i tried b\c\d but this one also didnt work.
Any help would be... (5 Replies)
Hello everyone,
My main objective is to search for text within a file, namely a block of text where each line ends with a backslash "\".
However, the block must begin with a keyword, like "loginstring".
Here is an example of a file that contains a block:
###############
loginstring \... (2 Replies)
Hi,
Could you please tell me how nawk command works when there is a asterisk <*> or space with asterisk < *> or <* > in the parameter.
I am just trying to read line by line and fetch fourth parameter separated by delimiter (|).
But if there is a * or < *> or <* > in the fourth parameter it... (7 Replies)
Hi, i have this script
setenv.sh
if
then
echo "is empty"
fi
echo "done"
The following is the result when i run the script from command without and with a dot and space operator
$ setenv.sh
is empty
done
$ . setenv.sh
sh: VAR_1: Parameter not set.
$
It's our standard to run... (5 Replies)
my program is designed to take the first parameters as extension, then the rest of the parameters as files to be searched for and, if found, modified by the extension. If not found, it prints an error.
Everything is great until: ./chExt.sh 'com' 'king cobra.dat'
where $file splits up the two... (2 Replies)
I wrote this script which works well when I manually input 55518622 and 1
but I need this script to be generic and loop over the following table
awk '$4>(55518622-500000) && $4<(55518622+500000)' chr1_GEN2bim | awk 'BEGIN {min=1000000000; max=0;}; {\
if($4<min && $4 != "") min = $4; if($4>max... (8 Replies)
Hi,
need help to pass an paremeter to for loop script
$cat tp.ksh
for i in `grep $1 | cut -d "/" -f 5 | cut -d" " -f2`
do
fgrep $i $1 | grep 'with value' | cut -d "|" -f 2
done
$tp.ksh test_data.plan_49989_2015-05-01-00-13-38.log
command doesnot return the values. (5 Replies)
Hi All,
I have created one function for KSH and was running well with one parameter input since I just had to use $1 to get the parameter.
Now I want to do loop for each parameter(actually filenames) . I have try to use do loop, but $i does not resolve to parameter instead it resolves to 1,... (5 Replies)
Discussion started by: mysocks
5 Replies
LEARN ABOUT DEBIAN
bup-margin
bup-margin(1) General Commands Manual bup-margin(1)NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS --predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO bup-midx(1), bup-save(1)BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown-bup-margin(1)