Sed command to globally replace xth occurance. Post: 302325227

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Top Forums Shell Programming and Scripting Sed command to globally replace xth occurance. Post 302325227 by lowmaster on Saturday 13th of June 2009 07:05:12 PM

06-13-2009

Registered User

Quote:

Originally Posted by ghostdog74

here's a more readable version

Code:

awk '{
 j=0
 for(i=1;i<=NF;i++){
   if ($i == "the"){        
        j++
        if (j==1) {
            $i = "those"
        }else if (j==3){
            $i = "these"
        }     
   }
 }
 print $0   
}
'  file

this looks absolutely beautiful, and it would be nice to work with, but I end up in this error:

+ awk '{ j=0 for(xi=1;xi<=NF;xi++){ if ($xi == "the"){j++ if (j==1) { $xi = "those" }else if (j==3){ $xi = "these" }}}print $0}'
awk: syntax error at source line 1
context is
{ j=0 >>> for <<< (xi=1;xi<=NF;xi++){ if ($xi == "the"){j++ if (j==1) { $xi = "those" }else if (j==3){ $xi = "these" }}}print $0}
awk: illegal statement at source line 1

However, the perl solution works great...

but how can I add a variable similar like this perl/sed mix (which ofcourse does not work this way):

Code:

perl -pe' s/\bthe\b/++$c==3?those ${kw2} :$c==1?these ${kw1} :$&/ges '

Thanx a lot!

Last edited by lowmaster; 06-13-2009 at 08:56 PM..

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