Hi,
whenever I am giving a 'ls' command system is going into infinite loop displaying the current home directory.
There is no separate shell script/file with ls name anywhere in the system.
I am using Solaris 10.
Any help / guidance in solving this problem is highly appreciated.
... (3 Replies)
hi all,
this is how my scrip looks like
#!/bin/sh
bindir='/opt/apps/script/bin'
datadir='/opt/apps/script/data'
dir='/opt/apps/script'
while : ; do
ls -1rt /opt/apps/script/data/check.txt*|tail -1 > /dev/null 2>&1
if ;then
chmod +rwx $bindir/dummy2.sh
... (8 Replies)
Hi All,
I need to run an infinite loop.
requirement below:
function1 --> creates a file file1
function2 ---> need to call if the file creates
i am running these both function via a script --> script.sh
i need to run the function1 first and if the file file1 creates then need to run the... (3 Replies)
1. The problem statement, all variables and given/known data:
My problem is an infinite loop when i press any other key other then Y or y in the while loop. what i want it to do is return to the normal script outside of it if pressing N or n or keep asking the same question if its any other... (4 Replies)
Hi, I was debating if I should put this in the dummies or scripts section, I apologize in advance if I chose poorly.
Fairly new to Unix and BASH scripting but I thought I made it fairly well given my limited understanding. However, the output indicates that it's looping and I'm ending up with a... (5 Replies)
Im unable to stop the below infinite loop (bash script). Can someone tell me why this isnt responding to signals eg: ctrl+c (SIGINT) or ctrl+z
c=0
test_loop() {
c=$(($c+1))
echo "count value is : $c "
sleep 1
test_loop
}
Im using: SunOS 5.10
PS: If run this as... (13 Replies)
Hi,
I was working on implementing error handling in my bash scripts, and decided to use trap to send myself an email incase of any errors. But it seems that somethings has gone wrong, and I am continuously getting same emails for an old error repeatedly (even though I have stopped/killed all... (1 Reply)
I have a script script.shwhich is scheduled to run at 11 AM everyday.
# script.sh Code:
./scb_script.sh &
unfortunately scb_script.sh is running today in infinite loop as respective files are not available.
My question, when script.sh starts running tomorrow, will the old process be... (1 Reply)
Hello Experts,
I have created one user confirmation process that will ask for user input. I have created one func for it. The issue is if i call it as normal then it works fine but if i am calling it in another script(in while loop) . It is going in infinite loop and not asking for user input. ... (8 Replies)
Discussion started by: looney
8 Replies
LEARN ABOUT LINUX
pldd
PLDD(1) Linux User Manual PLDD(1)NAME
pldd - display dynamic shared objects linked into a process
SYNOPSIS
pldd PID
pldd OPTION
DESCRIPTION
The pldd command displays a list of the dynamic shared objects that are linked into the process with the specified process ID. The list
includes the libraries that have been dynamically loaded using dlopen(3).
OPTIONS
-?, --help
Display program help message.
--usage
Display a short usage message.
-V, --version
Display the program version.
VERSIONS
pldd is available since glibc 2.15.
CONFORMING TO
The pldd command is not specified by POSIX.1. Some other systems have a similar command.
EXIT STATUS
On success, pldd exits with the status 0. If the specified process does not exist, the user does not have permission to access its dynamic
shared object list, or no command-line arguments are supplied, pldd exists with a status of 1. If given an invalid option, it exits with
the status 64.
EXAMPLE
$ echo $$ # Display PID of shell
1143
$ pldd $$ # Display DSOs linked into the shell
1143: /usr/bin/bash
linux-vdso.so.1
/lib64/libtinfo.so.5
/lib64/libdl.so.2
/lib64/libc.so.6
/lib64/ld-linux-x86-64.so.2
/lib64/libnss_files.so.2
NOTES
The command
lsof -p PID
also shows output that includes the dynamic shared objects that are linked into a process.
SEE ALSO ldd(1), lsof(1), dlopen(3), ld.so(8)GNU 2014-09-27 PLDD(1)