06-01-2009
Quote:
Originally Posted by
DeCoTwc
Thanks for the advice, shortly after posting I came up with some ideas using some basic if/else for the divide by 0 (though I've yet to try putting it into practice). I'm not sure what you mean by use >0 though?
check that denominator and numerator (or rather divisor, and divider?? forgot the english) are both more than 0, otherwise, how to divide, right? so do a simple if/else...
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DIV(3) Linux Programmer's Manual DIV(3)
NAME
div, ldiv, lldiv, imaxdiv - compute quotient and remainder of an integer division
SYNOPSIS
#include <stdlib.h>
div_t div(int numerator, int denominator);
ldiv_t ldiv(long numerator, long denominator);
lldiv_t lldiv(long long numerator, long long denominator);
#include <inttypes.h>
imaxdiv_t imaxdiv(intmax_t numerator, intmax_t denominator);
Feature Test Macro Requirements for glibc (see feature_test_macros(7)):
lldiv(): _XOPEN_SOURCE >= 600 || _ISOC99_SOURCE; or cc -std=c99
DESCRIPTION
The div() function computes the value numerator/denominator and returns the quotient and remainder in a structure named div_t that contains
two integer members (in unspecified order) named quot and rem. The quotient is rounded towards zero. The result satisfies quot*denomina-
tor+rem = numerator.
The ldiv(), lldiv(), and imaxdiv() functions do the same, dividing numbers of the indicated type and returning the result in a structure of
the indicated name, in all cases with fields quot and rem of the same type as the function arguments.
RETURN VALUE
The div_t (etc.) structure.
CONFORMING TO
SVr4, 4.3BSD, C89. The functions lldiv() and imaxdiv() were added in C99.
EXAMPLE
After
div_t q = div(-5, 3);
the values q.quot and q.rem are -1 and -2, respectively.
SEE ALSO
abs(3), remainder(3)
COLOPHON
This page is part of release 3.25 of the Linux man-pages project. A description of the project, and information about reporting bugs, can
be found at http://www.kernel.org/doc/man-pages/.
2007-07-26 DIV(3)