Hi,
I need to put the single line contents of a file into a variable, but remove the last character, for example the file would have this sort of contents:
2;4;3;10;67;54;96;
And I want the variable to be:
2;4;3;10;67;54;96 (notice the last ";" has gone).
Unfortunately I can't just... (4 Replies)
Hi...
i need a script to remove the space before and after the operator like( / ).
Ex :
Input file
apple / manago
mango / fresh apple / fresh
Desired output:
apple/manago
mango/fresh apple/fresh
Note: betwee the desired operator space should be removed, between words do not remove... (3 Replies)
Hi Experts,
I have data coming in 4 columns and there are new line characters \n in between the data. I need to remove the new line characters in the middle of the row and keep the \n character at the end of the line.
File is comma (,) seperated.
Eg:
ID,Client ,SNo,Rank
37,Airtel \n... (8 Replies)
Hi All,
I have output like this below
ldprod/03
ldprod/02
ldprod/01
ldprod/00
ldnprod/
ldnprod/030
I want only remove all character including /
ldprod
ldprod
ldprod
ldprod
ldprod
ldnprod (8 Replies)
Hi guys,
Does anyone know how to remove the last character in each of the line?
This is what I have:
ABCDE.1
GLSJD.2
HIJPL.2
HKAGB.3
IUBWQ.1
What I want (remove the dot and number):
ABCDE
GLSJD
HIJPL
HKAGB
IUBWQ
I tried to use this: sed 's/.*//'
But I'm not sure if that is... (3 Replies)
Hi there,
A total sed noob here. Is there a way using sed to delete everything before a character AND after another character on each line in a file? The deletion should also delete the indicating characters(here: an opening and a closing parenthesis).
The original file would look like... (3 Replies)
Below i am trying to remove "/" and "r" from the output, so i need output as:
hdiskpower3
hdisk0
hdisk1
#inq | grep 5773 | awk '{print $1}' | sed 's/dev//g' | awk -F"/" '{$1=$1}1'
.....................................................//rhdiskpower0
//rhdiskpower1
//rhdiskpower2... (3 Replies)
hello.
How to remove all characters in a line from first character ( a $ ) until and including the third occurrence of that character ( $ ).
Any help is welcome. (10 Replies)
Hi
I have file in below format. How i can remove the first and lost comma from this below file
,001E:001F,,,02EE,0FED:0FEF,
I need output has below
001E:001F,,,02EE,0FED:0FEF (6 Replies)
Discussion started by: ranjancom2000
6 Replies
LEARN ABOUT DEBIAN
bup-margin
bup-margin(1) General Commands Manual bup-margin(1)NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS --predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO bup-midx(1), bup-save(1)BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown-bup-margin(1)