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Top Forums Shell Programming and Scripting Shell script: returning the file with the most lines Post 302316787 by Breakology on Saturday 16th of May 2009 03:27:04 PM
Old 05-16-2009
Shell script: returning the file with the most lines

Hey I am relatively new to Linux and shell scripting, looking for a spot of help with a script I am working on.

I am writing a script that counts the number of lines in all the files in a directory, sorts them by line number and then returns ONLY the file with the most lines.

Right now I can accomplish the first part with
Code:
wc -l|sort -rn

but I do not know how to return only the file with the most lines in the output.
 

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service(8)						      System Manager's Manual							service(8)

NAME
service - run a System V init script SYNOPSIS
service SCRIPT COMMAND [OPTIONS] service --status-all service --help | -h | --version DESCRIPTION
service runs a System V init script in as predictable an environment as possible, removing most environment variables and with the current working directory set to /. The SCRIPT parameter specifies a System V init script, located in /etc/init.d/SCRIPT. The supported values of COMMAND depend on the invoked script. service passes COMMAND and OPTIONS to the init script unmodified. All scripts should support at least the start and stop commands. As a special case, if COMMAND is --full-restart, the script is run twice, first with the stop command, then with the start com- mand. service --status-all runs all init scripts, in alphabetical order, with the status command. EXIT CODES
service calls the init script and returns the status returned by it. FILES
/etc/init.d The directory containing System V init scripts. ENVIRONMENT
LANG, TERM The only environment variables passed to the init scripts. SEE ALSO
/etc/init.d/skeleton, update-rc.d(8), init(8), invoke-rc.d(8). Jan 2006 service(8)
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