Hi
It is possible with sed to print a pattern within a line matching regexp?
So, the line looks like : 19:00:00 blablablabla jobid 2345 <2>
the regexp is "jobid 2345" and the pattern is 56434.
That the code for find... (2 Replies)
trying to remove the portion in red:
Data:
mds_ar/bin/uedw92wp.ksh: $AI_SQL/wkly.sql
mds_ar/bin/uedw92wp.ksh: $EDW_TMP/wkly.sql
output to be:
mds_ar/bin/uedw92wp.ksh: wkly.sql
mds_ar/bin/uedw92wp.ksh: wkly.sql
SED i'm trying to use:
sed 's/:+\//: /g' input_file.dat >... (11 Replies)
I have a very large results file, and a list of filters
grep -wf filterlist.txt datafile.txt > outfile.txt
The above line works but is very slow and I'm wondering how to make it faster.
The items in my filterlist are only relevant to the first column. I don't care if any item in the... (1 Reply)
Hi,
i have data file like:
START1
a
b
STOP
c
d
START2
e
STOP
f
START3
g
STOP
When one of the START<count> variable is passed, i should print all lines matching this until the first 'STOP'
for example if 'START2' is provided for match, i should get the result as:
START2 (1 Reply)
Fairly straightforward, but I'm having an awful time getting what I thought was a simple regex to work. I'll give the command I was playing with, and I'm aware why this one doesn't work (the 1,3 is off the A-Z, not the whole expression), I just don't know what the fix is:
Actual Output(s):
$... (5 Replies)
Hi,
I am using the following code to fetch lines that are generated in last 1 hr . Hence, I am using date function to calculate -last 1 hr & the current hr and then somehow use awk (or sed-if someone could guide me better)
with some regex pattern.
dt_1=`date +%h" "%d", "%Y\ %l -d "1 hour... (10 Replies)
grep -v will exclude matching lines, but I want something that will print all lines but exclude a matching field. The pattern that I want excluded is '/mnt/svn'
If there is a better solution than awk I am happy to hear about it, but I would like to see this done in awk as well. I know I can... (11 Replies)
Hello,
I have two files file 1 and file 2 each having result of a query on certain database tables and need to compare for Col1 in file1 with Col3 in file2, compare Col2 with Col4 and output the value of Col1 from File1 which is a) not present in Col3 of File2 b) value of Col2 is different from... (2 Replies)
I have a line that I need to parse through and extract a pattern that occurs multiple times in it.
Example line:
getInfoCall: info received please proceed, getInfoCall: info received please proceed, getInfoCall: info received please proceed, getInfoCall: info received please proceed,... (4 Replies)
Discussion started by: Vidhyaprakash
4 Replies
LEARN ABOUT MOJAVE
english5.18
English(3pm) Perl Programmers Reference Guide English(3pm)NAME
English - use nice English (or awk) names for ugly punctuation variables
SYNOPSIS
use English;
use English qw( -no_match_vars ) ; # Avoids regex performance penalty
# in perl 5.16 and earlier
...
if ($ERRNO =~ /denied/) { ... }
DESCRIPTION
This module provides aliases for the built-in variables whose names no one seems to like to read. Variables with side-effects which get
triggered just by accessing them (like $0) will still be affected.
For those variables that have an awk version, both long and short English alternatives are provided. For example, the $/ variable can be
referred to either $RS or $INPUT_RECORD_SEPARATOR if you are using the English module.
See perlvar for a complete list of these.
PERFORMANCE
NOTE: This was fixed in perl 5.20. Mentioning these three variables no longer makes a speed difference. This section still applies if
your code is to run on perl 5.18 or earlier.
This module can provoke sizeable inefficiencies for regular expressions, due to unfortunate implementation details. If performance matters
in your application and you don't need $PREMATCH, $MATCH, or $POSTMATCH, try doing
use English qw( -no_match_vars ) ;
. It is especially important to do this in modules to avoid penalizing all applications which use them.
perl v5.18.2 2014-01-06 English(3pm)