Date difference between 2 dates in 'yyyy-mm-dd hh:mm:ss' format Post: 302304870

10 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

Format date from MM/DD/YYYY to YYYYMMDD

I have a file with some date columns in MM/DD/YYYY format: SMPBR|DUP-DO NOT USE|NEW YORK||16105|BA5270715|6/6/2007 |MWERNER|109||||JOHN||SMITH|MD|72211118||||||74559|21 WILMINGTON RD||D|11/6/2003|SL# MD CONTACT-LIZ RICHARDS|||0|Y|N||1411458| And I want to convert the date format to: ...

2. Shell Programming and Scripting

Sed: zero-padding dates (or: convert d/m/yyyy to dd/mm/yyyy)

3. UNIX for Advanced & Expert Users

fetch dates for last 36 days in format yyyy-mm-dd

can anyone please suggest me some ideas for writing a korn shell script which will go back to 36 days from current day and print each day (incremented by 1) in the format yyyy-mm-dd until the current day. Thanks Mark

4. Shell Programming and Scripting

date and time in mm/dd/yyyy hh:mm format

Frens, I have a logfile which has got manier things in it and somewer in that file i have a date in mm/dd/yyyy hh:mm format.... I just need to get the date and time nothing else.... i have searched in this forum for it but got only date in mm-dd-yyyy format.. but i need to search for...

5. Shell Programming and Scripting

change date format from yyyy/mm/dd to dd/mm/yyyy

(Attention: Green PHP newbie !) I have an online inquiry form, delivering a date in the form yyyy/mm/dd to my feedback form. If the content passes several checks, the form sends an e-mail to me. All works fine. I just would like to receive the date in the form dd/mm/yyyy. I tried with some code,...

6. Shell Programming and Scripting

Need date in the format [mm dd yyyy hh AM/PM]

could you please help be on the below code .. Requirement is when i pass the parameter(for below 2) i should get current time -2 hours in the format :wall:.. cur_dt=`$ICEBIN/sqsh -S$DSQUERY -U $BATCHID -P $PASSWD -h -C"select getdate()" | sed '2d'` pr_dt="`$ICEBIN/sqsh -S$DSQUERY -U $BATCHID...

7. Shell Programming and Scripting

need code for date which is in yyyy-mm-dd format

Hi, I am having one log files. contains som data according to date. And it is going to append .Eg:abc.log contains below data 2011-10-19 abjhgj 2011-10-19 gjhgjgj 2011-10-20 hhhjh 2011-10-20 hhhhjj 2011-10-21 gg . . . 2011-11-24 yyy from log files i want catch only...

8. Shell Programming and Scripting

Convert any date format into yyyy/mm/dd

How can I convert any user inputted date into yyyy/mm/dd ? For example user can input date one of the following 20120121 , 2012-01-21 ,01/21/2012,01/21/2012 etc But I need to convert any of the date entered by user into yyyy/mm/dd (2012/01/2012). Any suggestion. Thanks in advance this is...

9. Shell Programming and Scripting

Date Format MM/DD/YYYY

I am changing epoch times to dates. I was able to do the following: echo "$varx" | gawk '{print strftime("%c", $0)}' Mon Dec 31 16:26:40 2012 This changes the epoch date (which is what varx is) into localtime. However, my problem is that I only want 12/31/2012 and not the Mon Dec 31...

10. Shell Programming and Scripting

Date format YYYY/MM/DD to DD/MM/YYYY

I am getting output of YYYY-MM-DD and want to change this to DD/MM/YYYY. When am running the query in 'Todd' to_date(column_name,'DD/MM/YYYY') am getting the required o/p of DD/MM/YYYY, But when am executing the same query(Netezza) in linux server(bash) am getting the output of YYYY-MM-DD file...

LEARN ABOUT MOJAVE

datetime::leapsecond

DateTime::LeapSecond(3) 				User Contributed Perl Documentation				   DateTime::LeapSecond(3)

NAME

       DateTime::LeapSecond - leap seconds table and utilities

VERSION

       version 1.06

SYNOPSIS

	 use DateTime;
	 use DateTime::LeapSecond;

	 print "Leap seconds between years 1990 and 2000 are ";
	 print DateTime::Leapsecond::leap_seconds( $utc_rd_2000 ) -
	       DateTime::Leapsecond::leap_seconds( $utc_rd_1990 );

DESCRIPTION

       This module is used to calculate leap seconds for a given Rata Die day. It is used when DateTime.pm cannot compile the XS version of this
       code.

       This library is known to be accurate for dates until December 2009.

       There are no leap seconds before 1972, because that's the year this system was implemented.

       o   leap_seconds( $rd )

	   Returns the number of accumulated leap seconds for a given day, in the range 0 .. 22.

       o   extra_seconds( $rd )

	   Returns the number of leap seconds for a given day, in the range -2 .. 2.

       o   day_length( $rd )

	   Returns the number of seconds for a given day, in the range 86398 .. 86402.

SEE ALSO

       <http://hpiers.obspm.fr/eop-pc/earthor/utc/leapsecond.html>

       http://datetime.perl.org

AUTHOR

       Dave Rolsky <autarch@urth.org>

COPYRIGHT AND LICENSE

       This software is Copyright (c) 2013 by Dave Rolsky.

       This is free software, licensed under:

	 The Artistic License 2.0 (GPL Compatible)

perl v5.18.2							    2017-10-06						   DateTime::LeapSecond(3)

10 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

Format date from MM/DD/YYYY to YYYYMMDD

Discussion started by: ChicagoBlues

2. Shell Programming and Scripting

Sed: zero-padding dates (or: convert d/m/yyyy to dd/mm/yyyy)

Discussion started by: jgrogan

3. UNIX for Advanced & Expert Users

fetch dates for last 36 days in format yyyy-mm-dd

Discussion started by: pavan_test

4. Shell Programming and Scripting

date and time in mm/dd/yyyy hh:mm format

Discussion started by: smarty86