awk output in a variable Post: 302302967

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Hi, I am trying to use variable output in awk to append a string to a word in a line. But that is not happening. Could you please help me on this. YouTube Video Tutorial: How to Use Code Tags and Format Posts @UNIX.com The below is the code #!/bin/ksh set -x src=/users/oracle/Temp...

LEARN ABOUT CENTOS

shell-quote

SHELL-QUOTE(1)						User Contributed Perl Documentation					    SHELL-QUOTE(1)

NAME

       shell-quote - quote arguments for safe use, unmodified in a shell command

SYNOPSIS

       shell-quote [switch]... arg...

DESCRIPTION

       shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell.  This lets you process commands
       or files with embedded white space or shell globbing characters safely.	Here are a few examples.

EXAMPLES

       ssh preserving args
	   When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives.  It just joins them with spaces and
	   passes them to "$SHELL -c".	This doesn't work as intended:

	       ssh host touch 'hi there'	   # fails

	   It creates 2 files, hi and there.  Instead, do this:

	       cmd=`shell-quote touch 'hi there'`
	       ssh host "$cmd"

	   This gives you just 1 file, hi there.

       process find output
	   It's not ordinarily possible to process an arbitrary list of files output by find with a shell script.  Anything you put in $IFS to
	   split up the output could legitimately be in a file's name.	Here's how you can do it using shell-quote:

	       eval set -- `find -type f -print0 | xargs -0 shell-quote --`

       debug shell scripts
	   shell-quote is better than echo for debugging shell scripts.

	       debug() {
		   [ -z "$debug" ] || shell-quote "debug:" "$@"
	       }

	   With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can.

       save a command for later
	   shell-quote can be used to build up a shell command to run later.  Say you want the user to be able to give you switches for a command
	   you're going to run.  If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are
	   things the user can't pass through), you can do something like this:

	       user_switches=
	       while [ $# != 0 ]
	       do
		   case x$1 in
		       x--pass-through)
			   [ $# -gt 1 ] || die "need an argument for $1"
			   user_switches="$user_switches "`shell-quote -- "$2"`
			   shift;;
		       # process other switches
		   esac
		   shift
	       done
	       # later
	       eval "shell-quote some-command $user_switches my args"

OPTIONS

       --debug
	   Turn debugging on.

       --help
	   Show the usage message and die.

       --version
	   Show the version number and exit.

AVAILABILITY

       The code is licensed under the GNU GPL.	Check http://www.argon.org/~roderick/ or CPAN for updated versions.

AUTHOR

       Roderick Schertler <roderick@argon.org>

perl v5.16.3							    2010-06-11							    SHELL-QUOTE(1)

10 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

how to output awk to a variable

Discussion started by: bashirpopal

2. UNIX for Dummies Questions & Answers

Set a variable from awk output

Discussion started by: Cranie

3. Shell Programming and Scripting

AWK Output into a variable

Discussion started by: mace_560

4. Shell Programming and Scripting

using awk for setting variable but change the output of this variable within awk

Discussion started by: Cowardly