03-30-2009
Thank you pshaikh. it exactly gives the sizeof the structure. While executing your first sample piece of code... it is mostly &begin is greater than &end. Here all the local variables begin, end and array[100] gets stored in the stack. When you subtract the begin address and end address and divide it by the sizeof the array it gives the sizeof structure.
But if i try to subtract address of say &array[1] - &array[0] doesn't give the sizeof the array instead it gives 1 always. I just tried printing &array[1] and &array[0] which gives the address. When we subtract the address of begin and end variable it gives the number of bytes occupied between those two and why not in &array[1] - &array[0]. Kindly clarify.
Thanks
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LEARN ABOUT PHP
array_shift
ARRAY_SHIFT(3) 1 ARRAY_SHIFT(3)
array_shift - Shift an element off the beginning of array
SYNOPSIS
mixed array_shift (array &$array)
DESCRIPTION
array_shift(3) shifts the first value of the $array off and returns it, shortening the $array by one element and moving everything down.
All numerical array keys will be modified to start counting from zero while literal keys won't be touched.
Note
This function will reset(3) the array pointer of the input array after use.
PARAMETERS
o $array
- The input array.
RETURN VALUES
Returns the shifted value, or NULL if $array is empty or is not an array.
EXAMPLES
Example #1
array_shift(3) example
<?php
$stack = array("orange", "banana", "apple", "raspberry");
$fruit = array_shift($stack);
print_r($stack);
?>
The above example will output:
Array
(
[0] => banana
[1] => apple
[2] => raspberry
)
and orange will be assigned to $fruit.
SEE ALSO
array_unshift(3), array_push(3), array_pop(3).
PHP Documentation Group ARRAY_SHIFT(3)