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Top Forums Shell Programming and Scripting Rounding off decimals to the nearest number in PERL Post 302301942 by rdlover on Sunday 29th of March 2009 11:12:53 AM
Old 03-29-2009
Thanks Rikxik! I guess that's gonna work! I am trying to write a logical if else statement in Perl to use the 'ceil' and 'floor' functions , but my novice programming skills is hampering the progress!

This is what i am trying to accomplish , if the value of a variable $nSlice is a number greater than .5 (ex : 23.5 or 16.8 or 17.9 etc), ceil that number,else floor that number. Any suggestions or help would be appreciated. Thanks again!
 

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FLOOR(3M)																 FLOOR(3M)

NAME
fabs, floor, ceil, rint - absolute value, floor, ceiling, and round-to-nearest functions SYNOPSIS
#include <math.h> double floor(x) double x; double ceil(x) double x; double fabs(x) double x; double rint(x) double x; DESCRIPTION
Fabs returns the absolute value |x|. Floor returns the largest integer no greater than x. Ceil returns the smallest integer no less than x. Rint returns the integer (represented as a double precision number) nearest x in the direction of the prevailing rounding mode. NOTES
On a VAX, rint(x) is equivalent to adding half to the magnitude and then rounding towards zero. In the default rounding mode, to nearest, on a machine that conforms to IEEE 754, rint(x) is the integer nearest x with the additional stipulation that if |rint(x)-x|=1/2 then rint(x) is even. Other rounding modes can make rint act like floor, or like ceil, or round towards zero. Another way to obtain an integer near x is to declare (in C) double x; int k; k = x; Most C compilers round x towards 0 to get the integer k, but some do otherwise. If in doubt, use floor, ceil, or rint first, whichever you intend. Also note that, if x is larger than k can accommodate, the value of k and the presence or absence of an integer overflow are hard to predict. SEE ALSO
abs(3), ieee(3M), math(3M) 4th Berkeley Distribution May 12, 1986 FLOOR(3M)
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