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Full Discussion: find jpg's mkdir script help
Top Forums Shell Programming and Scripting find jpg's mkdir script help Post 302301587 by jedhypes on Friday 27th of March 2009 11:09:00 AM
Old 03-27-2009
Question find jpg's mkdir script help

I am having a problem getting this to work right. The script needs to search through directories and subdirectories. If a jpg is found then create a folder in that directory, so on and so forth. Here is what I have so far but it doesn't work right. Help please

#!/bin/bash
for d in `find ./ -type d`;
do
cd $d;
for f in *.{jpg,JPG};
do
mkdir jpgdir;
done;
cd -;
done;
 

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PUZZLE-DIFF(1)															    PUZZLE-DIFF(1)

NAME
puzzle-diff - Compare pictures with libpuzzle SYNOPSIS
[-b <contrast barrier for cropping>] [-c] [-C <max cropping ratio>] [-e] [-E <similarity threshold>] [-h] [-H <max height>] [-l <lambdas>] [-n <noise cutoff>] [-p <p ratio>] [-t] [-W <max width>] <file 1> <file 2> DESCRIPTION
puzzle-diff compares two pictures and outputs the normalized distance. Try puzzle-diff -h for more info. EXAMPLES
Output distance between two images: $ puzzle-diff pic-a-0.jpg pics-a-1.jpg 0.102286 Compare two images, exit with 10 if they look the same, exit with 20 if they don't (may be useful for scripts): $ puzzle-diff -e pic-a-0.jpg pics-a-1.jpg $ echo $? 10 Compute distance, without cropping and with computing the average intensity of the whole blocks: $ puzzle-diff -p 1.0 -c pic-a-0.jpg pic-a-1.jpg 0.0523151 AUTHORS
Frank DENIS libpuzzle at pureftpd dot org SEE ALSO
libpuzzle(3), puzzle_set(3) 2012-05-09 PUZZLE-DIFF(1)
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