error in if statement Post: 302298629

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1. Shell Programming and Scripting

parsing error in if statement

hello, I am trying to parse an error returned by a command inside the if statement but it is just displays the full error instead and then stops. if ; then echo "no such package" else echo "similar version found will use pkgrm" fi the above code just displays please let me know...

2. Shell Programming and Scripting

Error with if statement..Please help

:b:hi, I have a script as given below: pr_det="1" if then awk ' BEGIN {printf("%23s","session")}' >> report.txt awk ' BEGIN {printf "\n"} ' >> report.txt else awk ' BEGIN {printf("%55s","file_dsc")} ' >> report.txt awk ' BEGIN {printf("%101s","no_recs")} '...

3. Shell Programming and Scripting

Snytax error on If Statement--help

year=`date '+%Y'` month=`date '+%m'` day=`date '+%d'` day=`expr $day - 1` case $month in 1 | 3 | 5 | 7 | 8 | 10 | 12);; if($day =7 ); then $day=6 fi 4 | 6 | 9 | 11);; if ; then $day=31 fi 2);; if ; then if ; then

4. Linux

error in if statement

Hi , I am getting an error when I run the script for checking word "view" in a file . I am using if statement. like this if then VW_VAR=` cat $TN.${ecmdate}.sql1 | grep -i view | awk '{print $3}' | cut -d '.' -f2 ` echo " VW_$VW_VAR " sed -e...

5. Shell Programming and Scripting

Error in IF statement

HI i am getting error while executing the given statement for filename in `cat a/file.lst` do if then echo "Exit Code Description :File $filename - is missing in Input Directory" >a.log exit else count1=`awk 'END {print NR}' $filename` echo "$count1">>a.log count2=`awk 'END {print...

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hi, When i try to run the code below, i get the following error "ksh: syntax error: `(' unexpected" i am not able to figure it out. Can anyone help me? Code:

7. Shell Programming and Scripting

Error in if statement

I am working on script for stale nfs. the file consists of cat data01stale.log - - - - /abcd/backup - - - - /abcd/data Script

8. Shell Programming and Scripting

If statement Syntax error

Hi Can you please tell me what is wrong with this line: if && ]; then basically i want to check if x = 12 and F (Filename) end with 'g'. But it is throwing syntax error.

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Awk/if statement error

Can anybody tell the correct way to use the following awk pattern check within an if statement? When I run this command outside of the if statement cat /tmp/test2.out | awk -v T=$TIME -v G=$GROUP -v C=$CDATE '$0 ~ T && $0 ~ G && $0 ~ C' | grep -i "Starting the group" I get the following...

10. UNIX for Beginners Questions & Answers

Error code with if statement

hello all im new to unix and when i use below script i get an error : #! /bin/bash Echo -e "enter the name of the file : \c" read file_name if then echo "$file_name found" else echo "$file_name not found" fi running the script i get below error : $ ./hello

LEARN ABOUT PHP

crack_check

CRACK_CHECK(3)								 1							    CRACK_CHECK(3)

crack_check - Performs an obscure check with the given password

SYNOPSIS

       bool crack_check (resource  $dictionary, string	$password)

DESCRIPTION

       bool crack_check NULL (string  $password, string  $username = "", string  $gecos = "", resource	$dictionary)

	Performs an obscure check with the given password on the specified dictionary. The alternative signature also takes into account the user-
       name and the GECOS information.

       Warning

	      This function is EXPERIMENTAL. The behaviour of this function, its name, and surrounding documentation may change without notice	in
	      a future release of PHP. This function should be used at your own risk.

PARAMETERS

	      o $dictionary
		- The crack lib dictionary. If not specified, the last opened dictionary is used.

	      o $password
		- The password to be checked.

	      o $username
		- The username of the account with the password.

	      o $gecos
		- The GECOS information associated with the user account.

RETURN VALUES

	Returns TRUE if $password is strong, or FALSE otherwise.

CHANGELOG

       +--------+---------------------------------------------------+
       |Version |						    |
       |	|						    |
       |	|		     Description		    |
       |	|						    |
       +--------+---------------------------------------------------+
       |  0.3	|						    |
       |	|						    |
       |	|  The $username, $gecos and $dictionary parameters |
       |	| were added to the alternative signature.	    |
       |	|						    |
       +--------+---------------------------------------------------+
PHP Documentation Group 													    CRACK_CHECK(3)

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

parsing error in if statement

Discussion started by: rakeshou

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Error with if statement..Please help

Discussion started by: jisha

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Snytax error on If Statement--help

Discussion started by: dannyd_y

4. Linux

error in if statement

Discussion started by: capri_drm