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Top Forums UNIX for Advanced & Expert Users Grep a portion of the log file Post 302298569 by vidyadhar85 on Wednesday 18th of March 2009 02:38:47 AM
Old 03-18-2009
Quote:
Originally Posted by sainipardeep
Thanks Vidhya
But I dont know much about these editors. I am trying for a pattern like

grep -n "745100000000013" filename | while read line
do
echo "Line is --$LINE--"
done > outputfilename
try that awk or what you are trying to do is
Code:
 
grep -n "pattern" filename|awk -F":" '{print $1}' > temp_123
while read line ; do
li=$line
sed -n "$line,$((line+10))p" filename
echo "-----------------------------------------"
sed -n "$((li-10)),$((li))p" filename
done < temp_123

 

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GREP(1) 						      General Commands Manual							   GREP(1)

NAME
grep - search a file for lines containing a given pattern SYNOPSIS
grep [-elnsv] pattern [file] ... OPTIONS
-e -e pattern is the same as pattern -c Print a count of lines matched -i Ignore case -l Print file names, no lines -n Print line numbers -s Status only, no printed output -v Select lines that do not match EXAMPLES
grep mouse file # Find lines in file containing mouse grep [0-9] file # Print lines containing a digit DESCRIPTION
Grep searches one or more files (by default, stdin) and selects out all the lines that match the pattern. All the regular expressions accepted by ed and mined are allowed. In addition, + can be used instead of * to mean 1 or more occurrences, ? can be used to mean 0 or 1 occurrences, and | can be used between two regular expressions to mean either one of them. Parentheses can be used for grouping. If a match is found, exit status 0 is returned. If no match is found, exit status 1 is returned. If an error is detected, exit status 2 is returned. SEE ALSO
cgrep(1), fgrep(1), sed(1), awk(9). GREP(1)
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