Function Recursion Shift Problem Post: 302296941

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Top Forums UNIX for Dummies Questions & Answers Function Recursion Shift Problem Post 302296941 by nuvpal on Thursday 12th of March 2009 07:31:59 AM

03-12-2009

Registered User

Quote:

Originally Posted by radoulov

What's wrong with:

Code:

ls ~username

... or I'm missing something?

Could you post an example of the desired output?

I'm not quite sure what ls ~username would do, when I try it, it outputs the same as a normal ls command...

Basically what I want my script to do is display a visual representation of the specified directory and all its sub directories (like the tree command).

I have managed to supress the original ls error by adding the 2>/dev/null to the function call itself which seems to work ok now:

Code:

#!/bin/bash
direc=~
seperator=....
list=$(ls -l $direc | egrep '^d' | cut -d" " -f8)
function printList() {
        for line in $*
        do
                echo $line
                list=$(ls -l $direc/$1 | egrep '^d' | cut -d" " -f8 )
                direc=$direc/$1
                shift
                printList $list 2>/dev/null

        done
}
printList $list 2>/dev/null

But my script still does not work correctly, it will scan through the first directory found and display it along with all the subdirectories, but when it comes to loop back to the original directory and display the next directory it won't scan through and display the subdirectories of it. (I'm finding it quite hard to explain but I hope you can understand)

the output given will be something like: (where the . and number represent the directories and subdirectories)
direc1
direc1.1
direc1.1.1
direc1.1.2
direc1.2
direc1.2.1
direc2

and then it halts, where as i want it to display an output like:
direc1
direc1.1
direc1.1.1
direc1.1.2
direc1.2
direc1.2.1
direc2
direc2.1
direc2.1.1
direc2.2
direc2.2.1
direc3
direc3.1
direc3.1.1
direc3.2
direc4
...etc

Last edited by nuvpal; 03-12-2009 at 09:26 AM..

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LEARN ABOUT V7

diff3

DIFF3(1)						      General Commands Manual							  DIFF3(1)

NAME

       diff3 - 3-way differential file comparison

SYNOPSIS

       diff3 [ -ex3 ] file1 file2 file3

DESCRIPTION

       Diff3 compares three versions of a file, and publishes disagreeing ranges of text flagged with these codes:

       ====	       all three files differ

       ====1	       file1 is different

       ====2	       file2 is different

       ====3	       file3 is different

       The type of change suffered in converting a given range of a given file to some other is indicated in one of these ways:

       f : n1 a        Text is to be appended after line number n1 in file f, where f = 1, 2, or 3.

       f : n1 , n2 c   Text is to be changed in the range line n1 to line n2.  If n1 = n2, the range may be abbreviated to n1.

       The original contents of the range follows immediately after a c indication.  When the contents of two files are identical, the contents of
       the lower-numbered file is suppressed.

       Under the -e option, diff3 publishes a script for the editor ed that will incorporate into file1 all changes between file2 and file3,  i.e.
       the  changes  that  normally  would  be	flagged ==== and ====3.  Option -x (-3) produces a script to incorporate only changes flagged ====
       (====3).  The following command will apply the resulting script to `file1'.

		(cat script; echo '1,$p') | ed - file1

FILES

       /tmp/d3?????
       /usr/lib/diff3

SEE ALSO

       diff(1)

BUGS

       Text lines that consist of a single `.' will defeat -e.
       Files longer than 64K bytes won't work.

																	  DIFF3(1)

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