Hi, I'm trying to create a script that will display the contents of the users directories, but i'm confused about how to incorporate the shift properly.
The problem I'm getting with my script is that it goes throught the first couple of directories but then returns an error as it loses the first directory when continuing the search to other directories (I hope that makes sense?!)
EDIT: I apologise, that was the old problem, now the problem is the path to be searched adds the wrong directories so it looks in paths that do not exist
Here's my code, any help would be greatly appreciated.
Code:
direc=~
list=$(ls -l $direc | egrep '^d' | cut -d" " -f8)
function printList() {
for line in $*
do
echo $line
list=$(ls -l $direc/$1 | egrep '^d' | cut -d" " -f8)
direc=$direc/$1
shift
printList $list
done
}
printList $list
EDIT2: I have also tried suppressing the error returned by the ls to dev null by editing the line inside the function:
I'm using the UNIX csh and i wish to use recursion to nav my way up (or down as it is) a given folder.
My little test script is called "r" and takes a folder as argv (or $1)
#!/bin/tcsh -f
set allFiles = `ls -A $argv`
cd $argv
while ($#allFiles)
if (-d... (1 Reply)
Hello !
I need some help with my simple bash script.
This script removes all files ( with name given in $1 ) in current dir and subdirectories .
The problem is with first loop in the script ( for file in * ; do ) .
When I run the sript in my home directory this script display sometimes( ... (5 Replies)
Hello every body. I am trying to find the factorial using the following code. But it is giving the syntax error. I tried very much but in vain. Thanks in advance for helping me
factorial()
{
if
then
y=`expr $1 - 1`
x=$(( $1 \* factorial $y ))... (6 Replies)
I want to halt a tail recursive function after certain validation. I want to come out of entire recursion without unwinding phase. How can i achieve that . The coding is done in C language. (5 Replies)
Hi Guys,,
I tried to create a recursive function in unix.
The following is the code.
#/bin/sh
function(){
n=$1;
if ; then
out=1;
echo "inside if for 0";
else
out = `$n * function "$n-1"`;
echo "inside if for $n-1;
fi (3 Replies)
Sorry for my english
Hello all my friends and seniors, i had created a programm in c++
(anagrammig of word) it works fine but i cannot understand how exactly
recursion is working , i mean oh.. first look at the code .
#include <iostream>
#include <string>
... (1 Reply)
Hi,
Here is my code as below:
test.ksh:
=======
#!/bin/ksh
option="${1}"
while
do
case $1 in
-f) FILE="${2}"
echo "File name is $FILE"
;;
-d) DIR="${2}"
echo "Dir name is $DIR"
;;
-*)
echo "`basename ${0}`:usage: | " (5 Replies)
hey guys, im trying to learn bourne shell atm and I'm having some issues with functions.
so heres my code:
#!/bin/bash
##functions
memory () {
free -m
}
space () {
df -h
}
ip () { (5 Replies)
Hello,
I am reading one of the AIX manuals about shell scripting and (AIX 5) and I found this example when introducing to functions:
function usage
{
prog="$1"; shift
print -u2 "$prog: usage: $prog $@"
exit 1
}
This example is meant to be easy but I don't understand what it is... (5 Replies)
Hello Gurus :)
I'm "currently" (for the last ~2weeks) writing a script to build ffmpeg with some features from scratch.
This said, there are quite a few features, libs, to be downloaded, compiled and installed, so figured, writing functions for some default tasks might help.
Specialy since... (3 Replies)
Discussion started by: sea
3 Replies
LEARN ABOUT OSX
zipgrep
ZIPGREP(1L)ZIPGREP(1L)NAME
zipgrep - search files in a ZIP archive for lines matching a pattern
SYNOPSIS
zipgrep [egrep_options] pattern file[.zip] [file(s) ...] [-x xfile(s) ...]
DESCRIPTION
zipgrep will search files within a ZIP archive for lines matching the given string or pattern. zipgrep is a shell script and requires
egrep(1) and unzip(1L) to function. Its output is identical to that of egrep(1).
ARGUMENTS
pattern
The pattern to be located within a ZIP archive. Any string or regular expression accepted by egrep(1) may be used. file[.zip] Path
of the ZIP archive. (Wildcard expressions for the ZIP archive name are not supported.) If the literal filename is not found, the
suffix .zip is appended. Note that self-extracting ZIP files are supported, as with any other ZIP archive; just specify the .exe
suffix (if any) explicitly.
[file(s)]
An optional list of archive members to be processed, separated by spaces. If no member files are specified, all members of the ZIP
archive are searched. Regular expressions (wildcards) may be used to match multiple members:
* matches a sequence of 0 or more characters
? matches exactly 1 character
[...] matches any single character found inside the brackets; ranges are specified by a beginning character, a hyphen, and an end-
ing character. If an exclamation point or a caret (`!' or `^') follows the left bracket, then the range of characters within
the brackets is complemented (that is, anything except the characters inside the brackets is considered a match).
(Be sure to quote any character that might otherwise be interpreted or modified by the operating system.)
[-x xfile(s)]
An optional list of archive members to be excluded from processing. Since wildcard characters match directory separators (`/'),
this option may be used to exclude any files that are in subdirectories. For example, ``zipgrep grumpy foo *.[ch] -x */*'' would
search for the string ``grumpy'' in all C source files in the main directory of the ``foo'' archive, but none in any subdirectories.
Without the -x option, all C source files in all directories within the zipfile would be searched.
OPTIONS
All options prior to the ZIP archive filename are passed to egrep(1).
SEE ALSO egrep(1), unzip(1L), zip(1L), funzip(1L), zipcloak(1L), zipinfo(1L), zipnote(1L), zipsplit(1L)URL
The Info-ZIP home page is currently at
http://www.info-zip.org/pub/infozip/
or
ftp://ftp.info-zip.org/pub/infozip/ .
AUTHORS
zipgrep was written by Jean-loup Gailly.
Info-ZIP 28 February 2005 ZIPGREP(1L)
03-12-2009
