Sponsored Content
Full Discussion: unary operator expected
Top Forums Shell Programming and Scripting unary operator expected Post 302295013 by Corona688 on Friday 6th of March 2009 10:16:55 AM
Old 03-06-2009
If $j has no value at all, the expression will be invalid because it will vanish entirely, making it look like just [ -j 50 ]. Wrap $j in double-quotes and it won't vanish, becoming [ "" -lt 50 ] , which still isn't altogether sensible -- comparing a blank string to an integer -- but at least has correct syntax.
 

10 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

unary operator expected error

Hi I am doing a script like if then echo "table name dosent exist" exit fi the problem is if $table_name is null then i am getting the error Please help me Thanks in advance (2 Replies)
Discussion started by: ssuresh1999
2 Replies

2. UNIX for Dummies Questions & Answers

[: =: unary operator expected

HI, while running a script, I got the below mentioned error. /bin/sh: line10 : supportedMozillaVersion() { case "$*" in *rv:1.*) return 0;; *rv:.*) return 0;; *rv:*) return 1;; Mozilla\ 1.*) return 0;; Mozilla\ .*) return 0;; *) return 1;; esac } supportedFirefoxVersion() { case... (7 Replies)
Discussion started by: bhag281
7 Replies

3. Shell Programming and Scripting

unary operator expected

Im trying to fix my /etc/weekly that rotates various logs however it does them no matter what filesize they are and i want them to only do it if there file size exceeds 2M or something. So I'm playing with a script to get the filesize using a ls -l command which works and puts the value into a... (3 Replies)
Discussion started by: timgolding
3 Replies

4. Shell Programming and Scripting

line 5: [: -gt: unary operator expected

Hello all, :confused: I am not getting this error. Pls help me. ./construct_operon.sh: line 5: #!/bin/bash # Construct Operons using gene pairs. rm -rf operons_result lines=`awk 'END {print NR}' ecoli_operons` while ; do head -1 ecoli_operons | awk '{print $1"\n"$2}' > pattern ... (5 Replies)
Discussion started by: admax
5 Replies

5. UNIX for Dummies Questions & Answers

Error : -ne: unary operator expected

find . -name "*.*"|xargs grep WT:DBF_WL>> $F Wfexist=`cat $F|grep $i` echo $Wfexist if ; then echo $Wfexist echo "Workflow Exist" else touch $O chmod 777 $O echo $Wfexist echo $WfExist >> $O fi I am getting the error that -ne: unary operator expected in the line with red... (2 Replies)
Discussion started by: ritu.s
2 Replies

6. UNIX for Dummies Questions & Answers

Problem unary operator expected

I get the following error ./get_NE05: line 42: while do echo ${STRING_NAME} J=1 if ; then EXT=0$I else EXT=$I fi while do echo $I-$J #calculating last occurrence OCCURRENCE=`grep -io "${STRING_NAME}"... (3 Replies)
Discussion started by: f_o_555
3 Replies

7. Shell Programming and Scripting

unary operator expected

i=0 while Shell script reports an error "unary operator expected" pointing the above line. $i by default is 0 and holds integer value and $buf is also holding integer value. Please can some one let me know what is missing. Thanks. (1 Reply)
Discussion started by: sunrexstar
1 Replies

8. UNIX for Dummies Questions & Answers

: unary operator expected

Hiya all, Why do I get a :unary operator expected when I try to put a condition statement in my shell script (sh) like so and how to fix? if ; then echo "say hello" else echo "don't say hello" fi ? It seems if the script receives an argument it works but if I don't put an... (4 Replies)
Discussion started by: cyberfrog
4 Replies

9. UNIX for Dummies Questions & Answers

[: -gt: unary operator expected

Hi I have problem with my script. I dont now why but i don't change anything and script stop working. this is my code: #!/bin/sh for i in `ps -A | grep pocron.sh | grep -v grep | awk '{print $2}'` do COUNT=$((COUNT+1)) done ostatnie_wykonanie=`cat porader.log`... (1 Reply)
Discussion started by: fotex
1 Replies

10. Shell Programming and Scripting

Unary operator expected

In all my Googling, this usually happens when someone is comparing a variable, and that variable is unset. That doesn't appear to be the case for me... #!/bin/bash -x while read line do f=$(echo $line | tr -s ' ' | cut -d' ' -f 3) echo $f if then echo "This... (2 Replies)
Discussion started by: jnojr
2 Replies
ESCAPESHELLARG(3)							 1							 ESCAPESHELLARG(3)

escapeshellarg - Escape a string to be used as a shell argument

SYNOPSIS
string escapeshellarg (string $arg) DESCRIPTION
escapeshellarg(3) adds single quotes around a string and quotes/escapes any existing single quotes allowing you to pass a string directly to a shell function and having it be treated as a single safe argument. This function should be used to escape individual arguments to shell functions coming from user input. The shell functions include exec(3), system(3) and the backtick operator. On Windows, escapeshellarg(3) instead removes percent signs, replaces double quotes with spaces and adds double quotes around the string. PARAMETERS
o $arg - The argument that will be escaped. RETURN VALUES
The escaped string. EXAMPLES
Example #1 escapeshellarg(3) example <?php system('ls '.escapeshellarg($dir)); ?> SEE ALSO
escapeshellcmd(3), exec(3), popen(3), system(3), backtick operator. PHP Documentation Group ESCAPESHELLARG(3)
All times are GMT -4. The time now is 02:13 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy