Hi radoulov,

thanks a lot

i have got one more query

i have one file cpu and its content are:

Data Collected: 05/17/08 17:19:49

Refresh Interval: 600 seconds

GlancePlus Started/Reset: 05/17/08 08:19:45
B3692A GlancePlus C.03.72.00 17:29:49 UXAMSK01 9000/800 Current Avg High
-------------------------------------------------------------------------------
CPU Util SSUUUUU | 16% 9% 22%
Disk Util F | 1% 5% 12%
Mem Util SSSSSSSSSSUUUUUUUUBBBBB | 46% 45% 46%
Swap Util UUUURRRRR | 17% 16% 17%
-------------------------------------------------------------------------------
IO BY FILE SYSTEM Users= 8
Idx File System Device Type Logl IO Phys IO
--------------------------------------------------------------------------------
1 / /dev/vg00/lvol3 vxfs 24.8/ 25.1 0.5/ 0.5
2 /stand /dev/vg00/lvol1 hfs 0.0/ 0.0 0.0/ 0.0
3 /var /dev/vg00/lvol8 vxfs 0.2/ 0.3 1.9/ 2.1
4 /usr /dev/vg00/lvol7 vxfs 35.2/ 17.7 0.9/ 0.7

Top disk user: PID 11053, s_server 10.0 IOs/sec S - Select a Disk


Now i m using this code

sed -n '1p;8,10 {;s/^\([^ ]*\) [^0-9]*\([0-9]*%\).*$/\1 \2/p;}' cpu

to get output as:

Data Collected: 05/17/08 17:19:49
CPU 16%
Disk 1%
Mem 46%

i want to know few things about this code as to how it works
{;s/^\([^ ]*\) [^0-9]*\([0-9]*%\).*$/\1 \2/p;};
specially difference between ^ individually and like this [^ ]* and in this case
how it will directly take the second part of output i.e the % part bcoz in line 8-10
the % part comes after delimeter '|' so how does it actually work

and [^0-9]*\([0-9]*%) does it mean starting from 0-9 any character followed by 0-9 any charcter with % symbol

and what does this .*$ mean

and lastly this \1 \2/p;}; how does it work

Please help me





s/^\([^ ]*\)