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Top Forums Shell Programming and Scripting Replace a word with string from another file Post 302291302 by Tonda on Wednesday 25th of February 2009 10:54:13 AM
Old 02-25-2009
MySQL Replace a word with string from another file

Hi,

this belongs a little to my other post [1] but only at the starting point.

With
Code:
find -name "*.htm*"

i got a list like this:

Code:
./1999/01/file1.html
./1999/01/file2.html
./1999/02/file1.html
./2000/04/file1.html
./2000/04/file2.html
./2000/04/file3.html
./2000/file1.html
./2000/file2.html
./file1.html
./file2.html
./file3.html

Then i wrote a awk script who gives me this output:

Code:
./1999 | 1999| 1999 | author | mail/01 | 01 | 01 | author | mail/<title> | file1.html | file1.html | author | mail
./1999 | 1999| 1999 | author | mail/ 01 | 01 | 01 | author | mail/<title>|  file2.html | file2.html | author | mail
./2000  | 2000| 2000 | author | mail/<title> | file1.html | file1.html | author | mail
./2000 | 2000| 2000 | author | mail/<title> | file2.html | file2.html | author | mail
./<title> | file1.html | file1.html | author | mail
./<title> | file2.html | file2.html | author | mail

Now i need to replace the "<title>"-part with the real content between the <title>-tag of this file.

I fetch the content with another script:

Code:
for i in `find -name "*.htm*"`
do
    awk -F'<title>' -v RS='</title>' 'RT{print $NF}' $i
done

and put the output in a file "titles.txt":

Sitetitle 1
Sitetitle 2
Sitetitle 3
...

So, now i have two files who have the same number of lines. How i could replace <title> with Sitetitle 1 ?

It this the right way with two files or its better to fetch the content of <title>-tag in the first script?

Thanks in advance
Stefano

[1] https://www.unix.com/shell-programmin...dent-text.html

Last edited by Tonda; 02-26-2009 at 08:24 AM.. Reason: Fix a typo in title
 

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bup-margin(1)						      General Commands Manual						     bup-margin(1)

NAME
bup-margin - figure out your deduplication safety margin SYNOPSIS
bup margin [options...] DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids. For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by its first 46 bits. The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits, that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits with far fewer objects. If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if you're getting dangerously close to 160 bits. OPTIONS
--predict Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer from the guess. This is potentially useful for tuning an interpolation search algorithm. --ignore-midx don't use .midx files, use only .idx files. This is only really useful when used with --predict. EXAMPLE
$ bup margin Reading indexes: 100.00% (1612581/1612581), done. 40 40 matching prefix bits 1.94 bits per doubling 120 bits (61.86 doublings) remaining 4.19338e+18 times larger is possible Everyone on earth could have 625878182 data sets like yours, all in one repository, and we would expect 1 object collision. $ bup margin --predict PackIdxList: using 1 index. Reading indexes: 100.00% (1612581/1612581), done. 915 of 1612581 (0.057%) SEE ALSO
bup-midx(1), bup-save(1) BUP
Part of the bup(1) suite. AUTHORS
Avery Pennarun <apenwarr@gmail.com>. Bup unknown- bup-margin(1)
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