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Top Forums UNIX for Dummies Questions & Answers How do you create a zombie process? Post 302288089 by yvant on Monday 16th of February 2009 12:31:02 PM
Old 02-16-2009
Hello,

A ZOMBIE program is NOT something you want in your system.

It is a process that crashed and which is robbing memory space and/or cpu cycles.
They are detached from any terminals or processes that lauched it in the first place and are hard to kill. sometime only a reboot can get rid of it.

However, if you want to launch a program in the background there is 2 options to do so.

A) /usr/bin/your program &
B) nohup /usr/bin/your program

The differences lies in what your program do when you log out.
A) The program terminates upon login out
B) The program keep on running and only a kill or fuser command will stop it.
 

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fasthalt(8)						      System Manager's Manual						       fasthalt(8)

NAME
fasthalt - Halts the system SYNOPSIS
/usr/sbin/fasthalt [-lnq] DESCRIPTION
The fasthalt command halts the system and flags a subsequent reboot to skip the execution of fsck. The program creates the fastboot file, then invokes the halt program. The system start-up script contains instructions to look for the fastboot file. If present, the script removes the file and skips the invocation of the fsck command. If the command is invoked without the -l, -n, or -q flag, the halt program logs the shutdown using the syslogd command and places a record of the shutdown in the login accounting file, /var/adm/wtmp. Using the -q and the -n flags imply the -l flag. You must have root privileges to use this command. FLAGS
Does not log the halt using syslog. Prevents the sync before stopping, and does not log the halt using syslog. Causes a quick halt, does not log the halt using syslog, and makes no attempt to kill all processes. FILES
Specifies the command path Specifies the path of the syslog daemon RELATED INFORMATION
Commands: fsck(8), halt(8), syslogd(8) Functions: sync(2), syslog(3) delim off fasthalt(8)
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