Transpose data from columns to lines for each event
Hi everyone,
Maybe somebody could help me with this.
I have a text file showing in 2 columns registers of services used by customers in a comercial place.
The register for the use of any particular service begins with "EVENT" in column 1.
I would like to transpose the info for each block in one line. I mean, the different
words in column 1 will appear only once like a header, and the data in column 2
will appear below of its respective column in 1 line only.
Source file. (Not all blocks have the same registers in column 1, some have more than others)
I would like to tabulate it as follow
So far I know that If I use:
the result is the date (in column 2) for each register
11/01/2009
11/01/2009
11/01/2009
12/01/2009
But how can I follow to get want I want (the other columns below the respective header).
Hi,
I did read a few posts on the subjects, tried out a few solutions, but did not solve my problem.
https://www.unix.com/302121568-post11.html
https://www.unix.com/shell-programming-scripting/137953-large-file-columns-into-rows-etc-4.html
Please help. Problem very similar to the second link... (15 Replies)
I'm aware there are a lot of resources dedicated to the question of transposing rows and columns, but I'm a total newbie at this and the task appears to be beyond me.
I have 40 text files with content that looks like this:
Dokument 1 von 146
Orange County Register (California)
June 26, 2010... (2 Replies)
I have a data
A 1
B 2
C 3
D 4
E 5
i would like to change the data
A B C D E
1 2 3 4 5
Pls suggest how we can do it in UNIX.
Start using code tags, thanks. Also start reading your PM's you get from Mods as well read the Forum Rules. That might not do any harm. (24 Replies)
Any tips on how I can awk the input data to display the desired output per below? Thanking you in advance.
input test data:
2
2010-02-16 10:00:00
111111111111 bytes
99999999999 bytes
90%
4
2010-02-16 12:00:00
333333333333 bytes
77777777777 bytes
88%
5
2010-02-16 11:00:00... (4 Replies)
Hello. very new to shell scripting and would like to know if anyone could help me.
I have data thats being pulled into a txt file and currently have to manually transpose the data which is taking a long time to do.
here is what the data looks like.
Server1 -- Date -- Other -- value... (7 Replies)
Can I transform input like the below ?
Note: Insert zeros if there is no value to transform.
Input
key name score
key1 abc 10
key2 abc 20
key1 xxx 100
key2 xxx 20
key1 zzz 0
key2 zzz 29
key3 zzz 129
key1 yyy 39output
abc ... (1 Reply)
Hello to all, happy new year 2013!
May somebody could help me, is about a very similar problem to the problem I've posted here where the member rdrtx1 and bipinajith helped me a lot.
https://www.unix.com/shell-programming-scripting/211147-map-values-blocks-single-line-2.html
It is very... (3 Replies)
Hello,
I have a bilingual database with the following structure
a,b,c=d,e,f
The right half is in a Left to right script and the second is in a Right to left script as the examples below show
What I need is to separate out the database such that the first word on the left hand matches the first... (4 Replies)
Hello,
I have the following data and I want to use awk to transpose each value to a certain column , so in case the value is not available the column should be empty.
Example:
Box Name: BoxA
Weight: 1
Length :2
Depth :3
Color: red
Box Name: BoxB
Weight: 3
Length :4
Color: Yellow... (5 Replies)
Discussion started by: rahman.ahmed
5 Replies
LEARN ABOUT DEBIAN
log::log4perl::dateformat
DateFormat(3pm) User Contributed Perl Documentation DateFormat(3pm)NAME
Log::Log4perl::DateFormat - Log4perl advanced date formatter helper class
SYNOPSIS
use Log::Log4perl::DateFormat;
my $format = Log::Log4perl::DateFormat->new("HH:mm:ss,SSS");
# Simple time, resolution in seconds
my $time = time();
print $format->format($time), "
";
# => "17:02:39,000"
# Advanced time, resultion in milliseconds
use Time::HiRes;
my ($secs, $msecs) = Time::HiRes::gettimeofday();
print $format->format($secs, $msecs), "
";
# => "17:02:39,959"
DESCRIPTION
"Log::Log4perl::DateFormat" is a low-level helper class for the advanced date formatting functions in
"Log::Log4perl::Layout::PatternLayout".
Unless you're writing your own Layout class like Log::Log4perl::Layout::PatternLayout, there's probably not much use for you to read this.
"Log::Log4perl::DateFormat" is a formatter which allows dates to be formatted according to the log4j spec on
http://java.sun.com/j2se/1.5.0/docs/api/java/text/SimpleDateFormat.html
which allows the following placeholders to be recognized and processed:
Symbol Meaning Presentation Example
------ ------- -------------------
G era designator (Text) AD
y year (Number) 1996
M month in year (Text & Number) July & 07
d day in month (Number) 10
h hour in am/pm (1~12) (Number) 12
H hour in day (0~23) (Number) 0
m minute in hour (Number) 30
s second in minute (Number) 55
S millisecond (Number) 978
E day in week (Text) Tuesday
D day in year (Number) 189
F day of week in month (Number) 2 (2nd Wed in July)
w week in year (Number) 27
W week in month (Number) 2
a am/pm marker (Text) PM
k hour in day (1~24) (Number) 24
K hour in am/pm (0~11) (Number) 0
z time zone (Text) Pacific Standard Time
Z RFC 822 time zone (Text) -0800
' escape for text (Delimiter)
'' single quote (Literal) '
For example, if you want to format the current Unix time in "MM/dd HH:mm" format, all you have to do is this:
use Log::Log4perl::DateFormat;
my $format = Log::Log4perl::DateFormat->new("MM/dd HH:mm");
my $time = time();
print $format->format($time), "
";
While the "new()" method is expensive, because it parses the format strings and sets up all kinds of structures behind the scenes, followup
calls to "format()" are fast, because "DateFormat" will just call "localtime()" and "sprintf()" once to return the formatted date/time
string.
So, typically, you would initialize the formatter once and then reuse it over and over again to display all kinds of time values.
Also, for your convenience, the following predefined formats are available, just as outlined in the log4j spec:
Format Equivalent Example
ABSOLUTE "HH:mm:ss,SSS" "15:49:37,459"
DATE "dd MMM yyyy HH:mm:ss,SSS" "06 Nov 1994 15:49:37,459"
ISO8601 "yyyy-MM-dd HH:mm:ss,SSS" "1999-11-27 15:49:37,459"
APACHE "[EEE MMM dd HH:mm:ss yyyy]" "[Wed Mar 16 15:49:37 2005]"
So, instead of passing
Log::Log4perl::DateFormat->new("HH:mm:ss,SSS");
you could just as well say
Log::Log4perl::DateFormat->new("ABSOLUTE");
and get the same result later on.
Known Shortcomings
The following placeholders are currently not recognized, unless someone (and that could be you :) implements them:
F day of week in month
w week in year
W week in month
k hour in day
K hour in am/pm
z timezone (but we got 'Z' for the numeric time zone value)
Also, "Log::Log4perl::DateFormat" just knows about English week and month names, internationalization support has to be added.
COPYRIGHT AND LICENSE
Copyright 2002-2009 by Mike Schilli <m@perlmeister.com> and Kevin Goess <cpan@goess.org>.
This library is free software; you can redistribute it and/or modify it under the same terms as Perl itself.
perl v5.10.1 2010-07-21 DateFormat(3pm)