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Operating Systems Solaris crontab to run every 20 second Post 302270854 by pludi on Tuesday 23rd of December 2008 04:19:48 AM
Old 12-23-2008
No, it won't, instead it will run every 3 minutes (* == At any minute, /3 == every 3, */3 every 3 minutes, no matter what minute). AFAIK it's not possible to create a crontab entry for anything less than every minute.
If you really need to run something every 20 seconds, rather write a script that backgrounds and starts the desired action in a loop (using sleep or something alike).

HTH
 

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PARSE_TIME(3)						   BSD Library Functions Manual 					     PARSE_TIME(3)

NAME
parse_time, print_time_table, unparse_time, unparse_time_approx, -- parse and unparse time intervals LIBRARY
The roken library (libroken, -lroken) SYNOPSIS
#include <parse_time.h> int parse_time(const char *timespec, const char *def_unit); void print_time_table(FILE *f); size_t unparse_time(int seconds, char *buf, size_t len); size_t unparse_time_approx(int seconds, char *buf, size_t len); DESCRIPTION
The parse_time() function converts a the period of time specified in into a number of seconds. The timespec can be any number of <number unit> pairs separated by comma and whitespace. The number can be negative. Number without explicit units are taken as being def_unit. The unparse_time() and unparse_time_approx() does the opposite of parse_time(), that is they take a number of seconds and express that as human readable string. unparse_time produces an exact time, while unparse_time_approx restricts the result to only include one units. print_time_table() prints a descriptive list of available units on the passed file descriptor. The possible units include: second, s minute, m hour, h day week seven days month 30 days year 365 days Units names can be arbitrarily abbreviated (as long as they are unique). RETURN VALUES
parse_time() returns the number of seconds that represents the expression in timespec or -1 on error. unparse_time() and unparse_time_approx() return the number of characters written to buf. if the return value is greater than or equal to the len argument, the string was too short and some of the printed characters were discarded. EXAMPLES
#include <stdio.h> #include <parse_time.h> int main(int argc, char **argv) { int i; int result; char buf[128]; print_time_table(stdout); for (i = 1; i < argc; i++) { result = parse_time(argv[i], "second"); if(result == -1) { fprintf(stderr, "%s: parse error ", argv[i]); continue; } printf("-- "); printf("parse_time = %d ", result); unparse_time(result, buf, sizeof(buf)); printf("unparse_time = %s ", buf); unparse_time_approx(result, buf, sizeof(buf)); printf("unparse_time_approx = %s ", buf); } return 0; } $ ./a.out "1 minute 30 seconds" "90 s" "1 y -1 s" 1 year = 365 days 1 month = 30 days 1 week = 7 days 1 day = 24 hours 1 hour = 60 minutes 1 minute = 60 seconds 1 second -- parse_time = 90 unparse_time = 1 minute 30 seconds unparse_time_approx = 1 minute -- parse_time = 90 unparse_time = 1 minute 30 seconds unparse_time_approx = 1 minute -- parse_time = 31535999 unparse_time = 12 months 4 days 23 hours 59 minutes 59 seconds unparse_time_approx = 12 months BUGS
Since parse_time() returns -1 on error there is no way to parse "minus one second". Currently "s" at the end of units is ignored. This is a hack for English plural forms. If these functions are ever localised, this scheme will have to change. HEIMDAL
October 31, 2004 HEIMDAL
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