guys... I wanna use xargs in such a way that i can use it in grepping the fileds..
something like this:
grep -p <xargs values> *
lemme know how to do this.. (5 Replies)
Dear all,
I have to calculate sum of record count of files of the specified directory.
First I tried the following way which prints one or more outputs.
How can I sum of this output?
find /home/work/tmp/1/O/ -type f -print0 | xargs -0 wc -l | grep total
1666288 total
1073908 total
... (4 Replies)
Hello All,
I'm trying the following:find . -name "*" -exec grep -ln "IsAlpha" {} \;
It gives me file names only (having string "IsAlpha"), I want to get line numbers also, something like this: test 1: Line 52
test 1: Line 95 etc
Is it possible to obtain using grep & find only. (5 Replies)
I have been reading for a few hours trying to educate myself enough to accomplish this task, so please know I have performed some research. Unfortunately, I am not a *NIX scripting expert, or a coder. I come from a network background instead.
SO, here is my desired outcome. I have some Cisco... (5 Replies)
Hi
From the xargs man page (Solaris):
ls $1 | xargs -I {} -t mv $1/{} $2/{}
This would move all the files in directory $1 to directory $2
Problem 1:
In a shell script if I want to move files in d1 to d2
dir1=~/d1
dir2=~/d2
ls $dir1 | xargs -I {} -t mv $dir1/{} $dir2/{}
does not... (3 Replies)
Hello,
I'm interested in finding all occurrences of the terms in file1 in file2, which are both csv files. I can do this with a loop but I'm interested in knowing if I can also do it with the help of xargs and grep. What I have tried:
cat file1 | xargs grep file2
The problem is that... (15 Replies)
In a directory I have two lists, all files which could contain certain fields (they all share copied code) and a list of fields. My two scripts are
<appl.list xargs grep $1
where appl.list contains files (source programs) with the fields. This script is named YY
<fields.list xargs YY
... (4 Replies)
I entered the following <zzz.list xargs showtell |more which does a echo "<<<<<<<<<<<<<<<<<<<<<<<<< $1 >>>>>>>>>>>>>>>>>>"
head -20 $1 The file zzz.list contains 525 lines representing user scripts (1 per line), but only the first, 181st, and 399th lines were processed. What am I missing?
TIA (2 Replies)
Discussion started by: wbport
2 Replies
LEARN ABOUT LINUX
zegrep
ZGREP(1) General Commands Manual ZGREP(1)NAME
zgrep - search possibly compressed files for a regular expression
SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename...
DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code:
(-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the
standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep.
If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.
EXIT CODE
2 - An option that is not supported was specified.
AUTHOR
Charles Levert (charles@comm.polymtl.ca)
SEE ALSO grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)ZGREP(1)