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Top Forums UNIX for Dummies Questions & Answers Removing double quotes in a file Post 302269850 by kingofprussia on Thursday 18th of December 2008 08:06:38 PM
Old 12-18-2008
Removing double quotes in a file

Hi All,

I have a tab delimited file where each of the strings have double quotes.

The problem is that I have records which are in the following format:

"TEXAS" ""HOUSTON"" "123" "" "2625-39-39"
""MAINE"" "" "456" "I" "3737-39-82"

I would have to output another tab delimited file in the following fashion with the extra double quotes around the string removed:

"TEXAS" "HOUSTON" "123" "" "2625-39-39"
"MAINE" "" "456" "I" "3737-39-82"

This problem seems to persits across multiple fields and multiple rows.

Thanks for your help!!!
 

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ESCAPESHELLARG(3)							 1							 ESCAPESHELLARG(3)

escapeshellarg - Escape a string to be used as a shell argument

SYNOPSIS
string escapeshellarg (string $arg) DESCRIPTION
escapeshellarg(3) adds single quotes around a string and quotes/escapes any existing single quotes allowing you to pass a string directly to a shell function and having it be treated as a single safe argument. This function should be used to escape individual arguments to shell functions coming from user input. The shell functions include exec(3), system(3) and the backtick operator. On Windows, escapeshellarg(3) instead removes percent signs, replaces double quotes with spaces and adds double quotes around the string. PARAMETERS
o $arg - The argument that will be escaped. RETURN VALUES
The escaped string. EXAMPLES
Example #1 escapeshellarg(3) example <?php system('ls '.escapeshellarg($dir)); ?> SEE ALSO
escapeshellcmd(3), exec(3), popen(3), system(3), backtick operator. PHP Documentation Group ESCAPESHELLARG(3)
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