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Special Forums UNIX Desktop Questions & Answers problem while storing the output of awk to variable Post 302267379 by eswarreddya on Friday 12th of December 2008 08:54:32 AM
Old 12-12-2008
Java problem while storing the output of awk to variable

Hi,

i have some files in one directory(say some sample dir) whose names will be like the following.
some_file1.txt
some_file2.txt.

i need to get the last modified file size based on file name pattern like some_

here i am able to get the value of the last modified file size using the following command:
echo `ls -lt /sample/some_* |awk '{print $5}'` | `awk '{ F = " " ; print $1 }'


but the problem is, i need to store this value in one variable, and needs to print that variable value.

i tried several ways like the following.

SIZE=`echo `ls -lt /sample/some_* |awk '{print $5}'` | `awk '{ F = " " ; print $1 }'`
echo $SIZE

but it is not successful.


Your immediate help will be greatly appreciated

Reagrds,
Eswar
 

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IGAWK(1)							 Utility Commands							  IGAWK(1)

NAME
igawk - gawk with include files SYNOPSIS
igawk [ all gawk options ] -f program-file [ -- ] file ... igawk [ all gawk options ] [ -- ] program-text file ... DESCRIPTION
Igawk is a simple shell script that adds the ability to have ``include files'' to gawk(1). AWK programs for igawk are the same as for gawk, except that, in addition, you may have lines like @include getopt.awk in your program to include the file getopt.awk from either the current directory or one of the other directories in the search path. OPTIONS
See gawk(1) for a full description of the AWK language and the options that gawk supports. EXAMPLES
cat << EOF > test.awk @include getopt.awk BEGIN { while (getopt(ARGC, ARGV, "am:q") != -1) ... } EOF igawk -f test.awk SEE ALSO
gawk(1) Effective AWK Programming, Edition 1.0, published by the Free Software Foundation, 1995. AUTHOR
Arnold Robbins (arnold@skeeve.com). Free Software Foundation Nov 3 1999 IGAWK(1)
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