I'm looking to edit a file which contains various data including date.(ddmmyyyy)
I want to sort by date and then count the number of different dates found
Any ideas how to acheive this
Thanks in advance. (2 Replies)
Hi ,
I would like to list or sort by date and time (the files are named in day and time format) where the latest file will be placed at the bottom and the earliest file be placed at the top. Can anybody help me?
My files are named in the following manner.
EG: abc_071128_144121_data
"... (21 Replies)
Hi:
I am trying to create some script that sorts the files in a subdirectory by date and concatenates the thre most recently created files.
SAy,
file1 date1
file2 date2
file3 date3
file4 date4
file5 date5
file6 date6
i only want to concatenate the first three which are the most... (4 Replies)
Hi All,
Sorry to throw this frequent question but I lost my notes on it.
How do you list the files by date? I'm on red hat.
Thanks in advance,
itik (1 Reply)
Hi All,
I have two questions for sorting based on date.
Sample input:
2009/07/23 11:48:44|alpha
2009/07/23 11:48:44|gamme
2009/07/23 11:48:44|beta
2009/07/23 11:48:44|test
2009/07/23 11:48:44|data
2009/07/23 11:48:44|hello
2009/07/23 11:48:44|cat
Output:
2009/07/23... (3 Replies)
Hello,
I am still in trouble to sort log file in order by date as (YYYYDDD).
INFO :
YYYY = Year
DDD = Day in the year 001 for 1st January
Here is Input
New File: 95106 Oct 21 TAG__SC___2000229_0.TAB
New File: 95040 Mar 29 TAG__KSM__2012023_0.TAB
New File: 95106 Oct 21... (11 Replies)
Hi Experts,
I have a filelist collected from another server , now want to sort the output using date/time stamp filed.
- Filed 6, 7,8 are showing the date/time/stamp.
Here is the input:
#----------------------------------------------------------------------
-rw------- 1 root ... (3 Replies)
nawk '$1=="Date" {d=$(NF-2);next} $1=="Queue" {q=$NF;next} $1=="Forms"{print q, $NF, d}' OFS='|' printfile.log
I have this script working. Please let me know how to sort by Queue and then Date. (4 Replies)
Discussion started by: Daniel Gate
4 Replies
LEARN ABOUT DEBIAN
datefudge
DATEFUDGE(1) Debian DATEFUDGE(1)NAME
datefudge - pretend the system time is different
SYNOPSIS
datefudge [-s|--static] at_date program [arguments ...]
DESCRIPTION
datefudge is a small utility that pretends that the system time is different by pre-loading a small library which modifies the time(2),
gettimeofday(2) and clock_gettime(2) system calls.
OPTIONS --static, -s
set date as a `static' one. The above mentioned system calls will always return the date passed as a parameter of the program
regardless of time passing. See EXAMPLES below.
--help, -h
print short usage information and exit.
--version, -v
print version information and exit.
EXAMPLES
Basic example:
$ datefudge "2007-04-01 10:23" date -R
Sun, 01 Apr 2007 10:23:00 +0200
Non-static vs. static example:
$ datefudge "2007-04-01 10:23" sh -c "sleep 3; date -R"
Sun, 01 Apr 2007 10:23:03 +0200
$ datefudge --static "2007-04-01 10:23" sh -c "sleep 3; date -R"
Sun, 01 Apr 2007 10:23:00 +0200
AUTHOR
Written by Matthias Urlichs <smurf@noris.de>. Modified by Robert Luberda <robert@debian.org>.
BUGS
There is no attempt to make this change undetectable by the program. In particular, file modification times are not modified.
COPYRIGHT
Copyright (C) 2003 by Matthias Urlichs.
Copyright (C) 2008-2011 by Robert Luberda.
There is NO warranty; not even for MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. You may redistribute copies of datefudge under the
terms of the GNU General Public License.
For more information about these matters, see the file named COPYING.
SEE ALSO ld.so(1), time(2), gettimeofday(2), clock_gettime(2)datefudge 1.17 June 23th, 2011 DATEFUDGE(1)