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Top Forums Shell Programming and Scripting Replace part of a line with sed/awk Post 302260822 by alirezan on Friday 21st of November 2008 06:58:27 PM
Old 11-21-2008
Replace part of a line with sed/awk

Hello

I have a document and in this document I have several occurrence of "VAR == xxxxxxx" and xxxxx can be anything. I don't know what it is. I want to replace the 'xxxxx's with something I know.

What I know however, is the line numbers of the VAR =='s in the file.

How can I replace the xxxx's with awk or sed? Can someone please help me out here?

Thanks
Ali
 

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IGAWK(1)							 Utility Commands							  IGAWK(1)

NAME
igawk - gawk with include files SYNOPSIS
igawk [ all gawk options ] -f program-file [ -- ] file ... igawk [ all gawk options ] [ -- ] program-text file ... DESCRIPTION
Igawk is a simple shell script that adds the ability to have ``include files'' to gawk(1). AWK programs for igawk are the same as for gawk, except that, in addition, you may have lines like @include getopt.awk in your program to include the file getopt.awk from either the current directory or one of the other directories in the search path. OPTIONS
See gawk(1) for a full description of the AWK language and the options that gawk supports. EXAMPLES
cat << EOF > test.awk @include getopt.awk BEGIN { while (getopt(ARGC, ARGV, "am:q") != -1) ... } EOF igawk -f test.awk SEE ALSO
gawk(1) Effective AWK Programming, Edition 1.0, published by the Free Software Foundation, 1995. AUTHOR
Arnold Robbins (arnold@skeeve.com). Free Software Foundation Nov 3 1999 IGAWK(1)
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