Hi,
I have a date input in MMDDYYYY format..
I have to give the day (whether that DD is sunday/monday...)
Is there any command for it...
Or do I have to write a script for that...
Thanks in Advance
Yeheya (1 Reply)
It's easy as pie to get the date minus one day on opensolaris:
date -d "-1 day" +"%Y%m%d"run this command on our crappy Solaris 10 machines however (which I'm guessing doesn't have GNU date running on it) and you get:
date: illegal option -- d
date: illegal option -- 1
date: illegal option --... (5 Replies)
Hi guys,
I had a scenario...
1. I had to get the previous days date in yyyymmdd format
2. i had to create a file with Date inthe format yyyymmdd.txt format
both are different
thanks guys in advance.. (4 Replies)
Hello All,
I am writing a script in Sun Solaris
I want the date for "day before yesterday", i got the yesterday's date by this command TZ=GMT+24 date +%b" "%d.
Please suggest me some code to get the date for day before yesterday (6 Replies)
Hi All,
I have a file in the following format.I need to pick up 25th field which is a date and convert it into a day and add it as a field in the file.
"AAGENAS,PEARL... (3 Replies)
I need to get the next day's date of the user entered date
for example:
Enter date (yyyy/mm/yy):
2013/10/08I need to get the next day's date of the user entered date
Desired Output:
2013/10/09Though there are ways to achieve this is Linux or Unix environment (date command) ,I need to... (1 Reply)
Hi the below code is failing i am trying to generate do the following:
2014-10-22 11:26:00 (Substract 24 hrs)
should produce
2014-10-21 11:26:00
I need the same formatting below because that gets inputted into code for an... (4 Replies)
Hello Folks,
I have a variable output holding date as below -
output = "20141220"
I need to extract a day out of it and store it in another variable i.e. something similar to below -
output1=20141219"
and if the month is changing i.e. date in on 31st or 1st it should be taken care of
"date... (5 Replies)
I Have text like
XXX_20190908.csv.gz need to replace Only date in this format with current date every day
Thanks! (1 Reply)
Discussion started by: yamasani1991
1 Replies
LEARN ABOUT SUSE
cal
CAL(1) BSD General Commands Manual CAL(1)NAME
cal -- displays a calendar
SYNOPSIS
cal [-smjy13] [[[day] month] year]
DESCRIPTION
Cal displays a simple calendar. If arguments are not specified, the current month is displayed. The options are as follows:
-1 Display single month output. (This is the default.)
-3 Display prev/current/next month output.
-s Display Sunday as the first day of the week.
-m Display Monday as the first day of the week.
-j Display Julian dates (days one-based, numbered from January 1).
-y Display a calendar for the current year.
-V Display version information and exit.
A single parameter specifies the year (1 - 9999) to be displayed; note the year must be fully specified: ``cal 89'' will not display a calen-
dar for 1989. Two parameters denote the month (1 - 12) and year. Three parameters denote the day (1-31), month and year, and the day will
be highlighted if the calendar is displayed on a terminal. If no parameters are specified, the current month's calendar is displayed.
A year starts on Jan 1. The first day of the week is determined by the locale.
The Gregorian Reformation is assumed to have occurred in 1752 on the 3rd of September. By this time, most countries had recognized the ref-
ormation (although a few did not recognize it until the early 1900's.) Ten days following that date were eliminated by the reformation, so
the calendar for that month is a bit unusual.
HISTORY
A cal command appeared in Version 6 AT&T UNIX.
OTHER VERSIONS
Several much more elaborate versions of this program exist, with support for colors, holidays, birthdays, reminders and appointments, etc.
For example, try the cal from http://home.sprynet.com/~cbagwell/projects.html or GNU gcal.
AVAILABILITY
The cal command is part of the util-linux-ng package and is available from ftp://ftp.kernel.org/pub/linux/utils/util-linux-ng/.
BSD June 6, 1993 BSD