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Top Forums Shell Programming and Scripting converting day to capital letter... Post 302258512 by Ikon on Friday 14th of November 2008 05:27:01 PM
Old 11-14-2008
I dont know about AIX but, On my HP-UX I had to do the following:

Code:
OFFSET=${1:-1}

case $OFFSET in
  *[!0-9]* | ???* | 3? | 29) print -u2 "Invalid input" ; exit 1;;
esac

eval `date "+day=%d; month=%m; year=%Y`
typeset -Z2 day month
typeset -Z4 year

day=$((day - OFFSET))
if (( day <= 0 )) ;then
  month=$((month - 1))
  if (( month == 0 )) ;then
    year=$((year - 1))
    month=12
  fi
  set -A days `cal $month $year`
  xday=${days[$(( ${#days[*]}-1 ))]}
  day=$((xday + day))
fi

echo $day

 

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hdate_struct(3) 						libhdate C language						   hdate_struct(3)

NAME
hdate_struct - libhdate Hebrew date struct SYNOPSIS
#include <hdate.h> Data Fields int hd_day int hd_mon int hd_year int gd_day int gd_mon int gd_year int hd_dw int hd_size_of_year int hd_new_year_dw int hd_year_type int hd_jd int hd_days int hd_weeks Detailed Description libhdate Hebrew date struct Field Documentation int hdate_struct::hd_day The number of day in the hebrew month (1..31). int hdate_struct::hd_mon The number of the hebrew month 1..14 (1 - tishre, 13 - adar 1, 14 - adar 2). int hdate_struct::hd_year The number of the hebrew year. int hdate_struct::gd_day The number of the day in the month. (1..31) int hdate_struct::gd_mon The number of the month 1..12 (1 - jan). int hdate_struct::gd_year The number of the year. int hdate_struct::hd_dw The day of the week 1..7 (1 - sunday). int hdate_struct::hd_size_of_year The length of the year in days. int hdate_struct::hd_new_year_dw The week day of Hebrew new year. int hdate_struct::hd_year_type The number type of year. int hdate_struct::hd_jd The Julian day number int hdate_struct::hd_days The number of days passed since 1 tishrey int hdate_struct::hd_weeks The number of weeks passed since 1 tishrey Author Generated automatically by Doxygen for libhdate C language from the source code. Version 1.4 Sun Jan 8 2012 hdate_struct(3)
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