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Top Forums Shell Programming and Scripting Recursively hard linking files -- bonehead question Post 302256266 by scyphers on Sunday 9th of November 2008 12:10:33 AM
Old 11-09-2008
Question Recursively hard linking files -- bonehead question

I used to program ksh a while back, but I've been off in Oracle/Windows land (for clients -- not by choice) for so long that I can't remember what should be an easy thing. Here's the scenario:

1)Find all files and directories beneath some directory point (A).
2)If directory, make the subdirectory at some different directory point (B)
3)If file, link (not symbolic) the file in the correct subdirectory under point B.

For a more concrete example, here's a scenario.

Point A: /usr/test
Point B: /var/test

File structures:
/usr/test
/usr/test/oracle
/usr/test/oracle/script 1
/usr/test/oracle/script 2
/usr/test/db2
/usr/test/db2/script 1
/usr/test/db2/script 2

I'm trying to write a script that will result in the following output (and/or actually do the work instead of writing an output script, but I can live with creating a secondary script):

mkdir /var/test/oracle
ln /usr/test/oracle/"script 1" /var/test/oracle/"script 1"
ln /usr/test/oracle/"script 2" /var/test/oracle/"script 2"
mkdir /var/test/db2
ln /usr/test/db2/"script 1" /var/test/db2/"script 1"
ln /usr/test/db2/"script 2" /var/test/db2/"script 2"

Here's the pseudo code for what I've been working on so far:

#!/bin/bash

#declare variables
cnt=0 #array counter
# &1 == Source Directory
# &2 == Target Directory
source_len=awk '{ print length }'

# Find out what the subdirectories are
full_list=find $1 -print 2>/dev/null

## Populate the subdirectories into an array
## Trim the root from the subdirectories into a second array
subdir = full_list| cut -c source_len-

# Loop through, creating them one at a time.
if [-d full_list]
then
# make the new directory
echo "mkdir $target/$subdir"
elif [-f source]
then
# link the file
echo "ln $full_list $target/$subdir"
fi

Someone suggested to me mounting /usr/test to /var/test, but that doesn't completely satisfy the necessary requirements (and would result in a few thousand mount points being scattered through the environment -- not a pretty picture)...

if this was PL/SQL, it would have taken me about 15 seconds to write, but I'm rusty on bash scripting. Any thoughts?

--CS
 

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IGAWK(1)							 Utility Commands							  IGAWK(1)

NAME
igawk - gawk with include files SYNOPSIS
igawk [ all gawk options ] -f program-file [ -- ] file ... igawk [ all gawk options ] [ -- ] program-text file ... DESCRIPTION
Igawk is a simple shell script that adds the ability to have ``include files'' to gawk(1). AWK programs for igawk are the same as for gawk, except that, in addition, you may have lines like @include getopt.awk in your program to include the file getopt.awk from either the current directory or one of the other directories in the search path. OPTIONS
See gawk(1) for a full description of the AWK language and the options that gawk supports. EXAMPLES
cat << EOF > test.awk @include getopt.awk BEGIN { while (getopt(ARGC, ARGV, "am:q") != -1) ... } EOF igawk -f test.awk SEE ALSO
gawk(1) Effective AWK Programming, Edition 1.0, published by the Free Software Foundation, 1995. AUTHOR
Arnold Robbins (arnold@skeeve.com). Free Software Foundation Nov 3 1999 IGAWK(1)
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