10-16-2008
Quote:
Originally Posted by
G.K.K
Hi All,
i am facing an error in the korn shell by executing the following script, can anyone help me out in solving the error..
The script is to find the size of a directory.......
Note: /root/kamal is a directory
size_dir=$(du -s /root/kamal | cut -f1)
echo $size_dir
error: invalid $ at ( in size_dir
please help me in solving this, it would be greateful for me if any one help me in solving this..
Thanks & regards
kamal
please help me in solving this...
10 More Discussions You Might Find Interesting
1. Shell Programming and Scripting
Hi,
I am very confused with my printf command.
Somehow one variable can't line up with others...
newstart2 ="Mon Nov 11 01 00:00:00 2002"
printf "%-20s" $newstart2
Here is the output:
Mon Nov 11
01 00:00:00 2002
It spread out to two lines..
Why? (1 Reply)
Discussion started by: cin2000
1 Replies
2. UNIX for Dummies Questions & Answers
Hi,
I don't understand why the below code gave me error message:
worked: not found
I am using ksh program.
worked =`/usr/ucb/echo "scale=2; ($logend-$logstart)/3600" | bc`
Thank you very much for your help! (1 Reply)
Discussion started by: cin2000
1 Replies
3. Shell Programming and Scripting
I've created a script and copied it to another server and try to execute it at the same time but I'm getting a permission error.
I'm logged on as root and I gave the file 777 permission when I created it, but I can't run it remotely via ssh command because of permission issue.
Any ideas?
... (5 Replies)
Discussion started by: pdtak
5 Replies
4. Shell Programming and Scripting
Hi Guys,
while executing the following command : print "-ABC" is giving following error :
ksh: print: bad option(s)
I cannot use echo for some other reasons, so any other option ? (2 Replies)
Discussion started by: sagarjani
2 Replies
5. Shell Programming and Scripting
Sorry for the duplicate thread this one is similar to the one in
https://www.unix.com/shell-programming-scripting/88132-awk-sed-script-read-values-parameter-files.html#post302255121
Since there were no responses on the parent thread since it got resolved partially i thought to open the new... (4 Replies)
Discussion started by: rajan_san
4 Replies
6. Shell Programming and Scripting
Hi All
I am quite new to Unix. Following is a shell script that i have written and getting the subject mentioned error.
#!/bin/ksh
#-------------------------------------------------------------------------
# File: ang_stdnld.ksh
#
# Desc: UNIX shell script to extract Store information.... (3 Replies)
Discussion started by: amitsinha
3 Replies
7. Shell Programming and Scripting
Hello,
I am trying to run a remote file (y.ksh) using rsh.
In this action i want to use an environment variable TOOL=/home/macc1
i am running the rsh from profile macc on server1.
rsh server2 -l macc1 "$TOOL/y.ksh"
but i can see that the executable command = /home/macc/y.ksh and not... (1 Reply)
Discussion started by: LiorAmitai
1 Replies
8. Shell Programming and Scripting
Hi there,
I'm encountering problems on an AIX system when using following in my script.
find . -name *.edi -type f -exec sh -c 'scp {} $user@$server:$path || exit 5; mv {} $sent || exit 7' \;
the error i get is following
find: 0652-018 An expression term lacks a required... (4 Replies)
Discussion started by: Kerberos
4 Replies
9. Shell Programming and Scripting
I probably read all the threads in almost all the forums for a solution to my need. I am a beginner in shell scripting and I dont have a perfect solution yet. Below is my code snippet.
idql -n $REPOSITORY_NAME.$cs -Udmadmin -P"" -R$DM_SCRIPTS/test.api > /dev/null 2>&1
if ; then
echo... (7 Replies)
Discussion started by: vishnudev1
7 Replies
10. Shell Programming and Scripting
I am trying to use awk command withing ksh.
ksh "echo \"my name\" | awk '{print $2}'"
I am getting out as :
my name
Expected output:
name
When I use
echo "my name" | awk '{print $2}'
I am getting the correct output:
name
I am not sure what mistake I am doing when using awk... (1 Reply)
Discussion started by: Bala_db2
1 Replies
SETUID(1) General Commands Manual SETUID(1)
NAME
setuid - run a command with a different uid.
SYNOPSIS
setuid username|uid command [ args ]
DESCRIPTION
Setuid changes user id, then executes the specified command. Unlike some versions of su(1), this program doesn't ever ask for a password
when executed with effective uid=root. This program doesn't change the environment; it only changes the uid and then uses execvp() to find
the command in the path, and execute it. (If the command is a script, execvp() passes the command name to /bin/sh for processing.)
For example,
setuid some_user $SHELL
can be used to start a shell running as another user.
Setuid is useful inside scripts that are being run by a setuid-root user -- such as a script invoked with super, so that the script can
execute some commands using the uid of the original user, instead of root. This allows unsafe commands (such as editors and pagers) to be
used in a non-root mode inside a super script. For example, an operator with permission to modify a certain protected_file could use a
super command that simply does:
cp protected_file temp_file
setuid $ORIG_USER ${EDITOR:-/bin/vi} temp_file
cp temp_file protected_file
(Note: don't use this example directly. If the temp_file can somehow be replaced by another user, as might be the case if it's kept in a
temporary directory, there will be a race condition in the time between editing the temporary file and copying it back to the protected
file.)
AUTHOR
Will Deich
local SETUID(1)