Sponsored Content
Top Forums Shell Programming and Scripting find command nonrecurslu listing ls -lrt Post 302240855 by RahulJoshi on Friday 26th of September 2008 08:33:36 PM
Old 09-26-2008
Thanks all ,but this code show error :
find . -maxdepth 1 -type f -exec ls -lrt {} \;
find: 0652-017 -maxdepth is not a valid option.

please resove this problem.
 

10 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

Find files older than 5 days and remove tem after listing

need help with this ... Find files older than 5 days and remove tem after listing list "test" file older than 5 days and then remove them (1 Reply)
Discussion started by: ypatel6871
1 Replies

2. Shell Programming and Scripting

Find problem listing directories even -type f

Hi All, #!/bin/ksh find /home/other -ls -type f -xdev | sort -nrk7 | head -2 >bigfile.txt The above is my script, which writes the large file into a file called bigfile.txt. My script contains only the above two lines. after execution i am getting the output like find: cannot chdir to... (1 Reply)
Discussion started by: Arunprasad
1 Replies

3. UNIX for Dummies Questions & Answers

using ls -lrt instead of ls

I have a requirement in which I shud use ls -lrt instead of ls command because when we use ls command we get an error..the script part where i get error is given below for SAPRESPONSEFILES in `ls $SAPRESPONSEGOFILE | sed "s/go/dat/g"` basically the script processes the files of format... (11 Replies)
Discussion started by: praviper
11 Replies

4. UNIX for Dummies Questions & Answers

find command -- listing files twice

I noticed the other day that after i used the find command to search for some files, the computer listed them twice -- first with just the names of the files (meaning ./(then the individual file names), then with the directory name, followed by the file names (./directory name/file name). I was... (2 Replies)
Discussion started by: Straitsfan
2 Replies

5. UNIX for Dummies Questions & Answers

Long listing of files using find command on remote server via SSH

Hi , I am trying to find some files on a remote machine using the find command. >ssh -q atukuri@remotehostname find /home/atukuri/ -name abc.txt /home/atukuri/abc.txt The above command works fine and lists the file, but if I want to do a long listing of files (ls -l) its not working . ... (2 Replies)
Discussion started by: atukuri
2 Replies

6. Shell Programming and Scripting

Problems with ls -lrt

I am doing ls -lrt and it does not respond and have to close the xterm ls works ok (4 Replies)
Discussion started by: kristinu
4 Replies

7. Shell Programming and Scripting

find command listing

Hello, I have been trying to understand how the 'find' command lists the search results. I have a list of songs in different file formats (mp3, wav, aac etc) in a huge directory hierarchy organized by genre and am trying to get the list of all songs of a particular format. I found ls -R... (9 Replies)
Discussion started by: ajayram
9 Replies

8. UNIX for Dummies Questions & Answers

What does total no. of files in ls -lrt o/p means?

when we fire ls -lrt command we see o/p as total 16 drwx------ 9 root root 8192 May 8 2002 lost+found drwxr-xr-x 2 root root 512 Jun 14 2002 TT_DB drwxrwxr-x 2 root root 512 Jul 31 2002 mail here total no. of files is always greater than... (4 Replies)
Discussion started by: Jcpratap
4 Replies

9. UNIX for Dummies Questions & Answers

Listing only the files under a directory from the result of find command

Hi, I have a main folder 'home'. Lets say there is a folder 'bin' under 'home'. I want to check the list of files under subdirectories present under the /bin directory created in the last 24 hours. I am using the following find command under home/bin directory: find . -mtime -1 -print ... (3 Replies)
Discussion started by: DJose
3 Replies

10. AIX

Getting files through find command and listing file modification time upto seconds

I have to list the files of particular directory using file filter like find -name abc* something and if multiple file exist I also want time of each file up to seconds. Currently we are getting time up to minutes in AIX is there any way I can get file last modification time up to seconds. (4 Replies)
Discussion started by: Nitesh sahu
4 Replies
SHELL-QUOTE(1)						User Contributed Perl Documentation					    SHELL-QUOTE(1)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.16.3 2010-06-11 SHELL-QUOTE(1)
All times are GMT -4. The time now is 02:13 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy