This solution has a problem because for which var_5 value I have a var_7 value and it can or can not be the same from others var_7 along the file. What I want is the var_7 value just after the specific var_5 value.
How to find the first day of previous month in unix mmddyyyy format?
example : today is 07052007 (in mmddyyyy)
output sud be 06012007
thanks
mohapatra (10 Replies)
Hi All,
I need to find the previous month last day minus one day, using shell script. Can you guys help me to do this.
My Requirment is as below:
Input for me will be 2000909(YYYYMM)
I need the previous months last day minus 1 day timestamp. That is i need 2000908 months last day minus ... (3 Replies)
Hi guys,
i have the follow problem i need to delete 10 row before the pattern and 1 after and the pattern row itself.
file looks like:
frect 9.8438 25.8681 10.625 25
. dynprop \
(# \
(call fox_execute(__self))) \
(FOX_VAR_29 \
... (4 Replies)
Hi,
on our hp-ux box we have 100s of shell scripts in a bin folder.
Now i have to figure out which scripts are not being used at all.
The timestamp for these are the ones when they were promoted to this 'bin' folder.
Now, how can I find when was the last time each of these scripts were run?
I... (2 Replies)
Suppose there are log entries like
16 Jul 2012 11:46:45,628 SendToClientService ExecuteThread: '256' for queue: 'weblogic.kernel.Default (self-tuning)': Received an unknown fault.
16 Jul 2012 11:47:45,650 SendToClientService ExecuteThread: '256' for queue: 'weblogic.kernel.Default... (4 Replies)
Hi Experts,
i am using the below code get the date of previous day.
#!/usr/bin/ksh
datestamp=`date '+%Y%m%d'`
yest=$((datestamp -1))
echo $yest
When i execute the code i am getting output as:
20130715
What i am trying here is, based on the date passed i am fetching previus day's... (0 Replies)
Hi,
How to change the filenames with timestamp in sub folders
I have the following code to select the records.
find . -type f -name '*pqr*' -ctime 1 -print
The following is the example
app_root_dir="/`echo $ScriptDir | cut -d'/' -f2`"
$app_root_dir/../BadFiles directory
uvw.bad... (3 Replies)
Hello All,
I have a directory containing of many .dat file, but with different naming conventions.
I want to delete files which are created before and on 10th September 2013.
I tried this command to see files which are are the files created before 10th September
find path/to/file -type... (6 Replies)
Hi,
How can I get files which are modified only in last minute ? it should not display 2 minutes back filels -la
-rw-rw-r-- 1 stuser st 51 Dec 3 09:22 a.csv
-rw-rw-r-- 1 stiser st 50 Dec 3 09:25 b.csv
-rw-rw-r-- 1 stuser st 53 Dec 3 09:33 c.csv
When I run command at 9:34am then I... (7 Replies)
Used below command to get list of files sorted by timestamp
find -L . -type f -name '*dat*' | xargs ls -ltrg
I want to get only the filenames so I tried adding basename but it doenst work , can some one advise on how to get only file name (1 Reply)
Discussion started by: lalitpct
1 Replies
LEARN ABOUT DEBIAN
shell-quote
SHELL-QUOTE(1p) User Contributed Perl Documentation SHELL-QUOTE(1p)NAME
shell-quote - quote arguments for safe use, unmodified in a shell command
SYNOPSIS
shell-quote [switch]... arg...
DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands
or files with embedded white space or shell globbing characters safely. Here are a few examples.
EXAMPLES
ssh preserving args
When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and
passes them to "$SHELL -c". This doesn't work as intended:
ssh host touch 'hi there' # fails
It creates 2 files, hi and there. Instead, do this:
cmd=`shell-quote touch 'hi there'`
ssh host "$cmd"
This gives you just 1 file, hi there.
process find output
It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to
split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote:
eval set -- `find -type f -print0 | xargs -0 shell-quote --`
debug shell scripts
shell-quote is better than echo for debugging shell scripts.
debug() {
[ -z "$debug" ] || shell-quote "debug:" "$@"
}
With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can.
save a command for later
shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command
you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are
things the user can't pass through), you can do something like this:
user_switches=
while [ $# != 0 ]
do
case x$1 in
x--pass-through)
[ $# -gt 1 ] || die "need an argument for $1"
user_switches="$user_switches "`shell-quote -- "$2"`
shift;;
# process other switches
esac
shift
done
# later
eval "shell-quote some-command $user_switches my args"
OPTIONS --debug
Turn debugging on.
--help
Show the usage message and die.
--version
Show the version number and exit.
AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions.
AUTHOR
Roderick Schertler <roderick@argon.org>
perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)