It's basically equivalent to awk -v user="$f" -F : '$1 == user { print $5 }' if you prefer that. It prints the fifth field when there is a match on the first. (The sed script additionally prunes anything after the first comma; you can do that with sub in awk.)
Actually this could be a place to finally actually implement the putting of pipes between the values!
If your awk doesn't understand -v, see if you have nawk or gawk or mawk
Last edited by era; 09-04-2008 at 07:25 AM..
Reason: Finally implement pipes between values
Hi,
Suppose I have a programme called Menu. This menu has various choices as we would expect from a Menu.
Now Can you Please help me as I want the details of the Users to be registered to some file , Whoever has entered this particular Program . Basically to see the username and the time that... (2 Replies)
Im "supporting" at least 2500 HP-UX workstations with CAD-related software with the B.11.11 build. I cant say anymore than that because of my companys sligtly paranoid security policy .
The last few days a new problem has arised from nowhere.
The problem is that users gets logged off when the... (5 Replies)
Discussion started by: Laoinjo
5 Replies
4. Post Here to Contact Site Administrators and Moderators
I have searched the forums but have not mangaed to quite find what im looking for. I have used to /etc/passwd command to present me a list of all users the who command to present all users currently logged on, but what i want to know is what command can i use to display users that are registered... (12 Replies)
How can I get the list of logged in users in the system programmatically?
I can get the list with 'who' or 'users' commands but I need to get the list programmatically...
May someone help, please?
Thanks in advance. (2 Replies)
How do I find this out? I have a feeling its a simple command such as who, but I just don't know what it is. I've had a search on here but either I can't put it into the right search criteria or there isn't a topic on it.
Thanks.
EDIT: Delete this thread, as I posted it I noticed the... (0 Replies)
I have 2 systems. (1) RHEL5 and (2) winXP pro
from xpPRO putty i ssh into rhel5 : user root
from xpPRO i ftp into rhel5 : user abc123
when i run #uptime it only shows 1 user
when i do #ps -u abc123 : it shows vsftpd deamon PID
is there a command that can be used to show all currently... (4 Replies)
Hi,
How to find the users who did not login into a UNIX box (thru ssh/ftp or any other way) for last 90 days?
I think of using "finger" or "last" command to findout each user's last login and then find number of days between today and that day. Is there any other better way or anyone prepared... (1 Reply)
So I'm trying to write a single line command So I have to use last first in this command and I've figured out the format my professor wants it in, something like thislast | cut -d' ' -f1,15 | sort > check | uniq -c.... and I never can get it right, when I just last command I get something... (2 Replies)
Discussion started by: DoubleAlpha
2 Replies
LEARN ABOUT CENTOS
igawk
IGAWK(1) Utility Commands IGAWK(1)NAME
igawk - gawk with include files
SYNOPSIS
igawk [ all gawk options ] -f program-file [ -- ] file ...
igawk [ all gawk options ] [ -- ] program-text file ...
DESCRIPTION
Igawk is a simple shell script that adds the ability to have ``include files'' to gawk(1).
AWK programs for igawk are the same as for gawk, except that, in addition, you may have lines like
@include getopt.awk
in your program to include the file getopt.awk from either the current directory or one of the other directories in the search path.
OPTIONS
See gawk(1) for a full description of the AWK language and the options that gawk supports.
EXAMPLES
cat << EOF > test.awk
@include getopt.awk
BEGIN {
while (getopt(ARGC, ARGV, "am:q") != -1)
...
}
EOF
igawk -f test.awk
SEE ALSO gawk(1)
Effective AWK Programming, Edition 1.0, published by the Free Software Foundation, 1995.
AUTHOR
Arnold Robbins (arnold@skeeve.com).
Free Software Foundation Nov 3 1999 IGAWK(1)