I'm trying to write a simple script that takes all the .tar.gz files in a directory and verifies them by using the gzip -tv command:
Code:
for zip in *.tar.gz
do
gzip -tv $zip
if [ #? -eq 0 ] ; then #Check return code from tar
echo "File ${zip} verified OK."
exit 0
else
echo "File ${zip} failed to verify. Please check."
exit 1
fi
done
However, when I try to run this, I get the following error:
Code:
./integcheck.sh: line 10: syntax error near unexpected token `else'
./integcheck.sh: line 10: ` else'
The script looks right to me, can someone help me out with what I missed? Is it a combination of the for/if/then statements?
I am trying to create a shell that asks the user to enter their name, and compare it to my own by saying we have the same name or saying my name and that they have a nice name too. Here is my script...
#!/bin/bash-x
echo "Enter your name".
read name
if
then
echo "My name is Adam too"... (1 Reply)
I'm running mysql in a bash script
mysql <<EOF
query
EOF
one query is like this:
UPDATE $dbname.$prefix"config" SET value = $var WHERE "$prefix"config.name = 'table colname';
with variable
but it's giving an error
i'm not sure what to put for
"$prefix"config.name
the table... (3 Replies)
ec2addtag --region us-west-1 vol1234 --tag Name=$nameinst;
It should execute
ec2addtag --region us-west-1 vol1234 --tag Name=webserver;
Instead it thinks that Name is equal to that variable. Please help. Thanks!
Please use code tags! (0 Replies)
howdy,
so I'm make a plugin work for Nagios, and the commandline is:
/usr/lib/nagios/plugins/check_mssql -H MySQLServerName -u MySqlAccountName -p MyPassword(#XXXXX -d MyDatabaseName
it is barfing with:
bash: syntax error near unexpected token `('
Thoughts?
Do I have to wrap something... (2 Replies)
The below bash function uses multiple variables CODING, SAMPLE, SURVEY, andvariant
in it. The user selects the cap function and details are displayed on the screen using the $SURVEY variable, the directory is changed to $SAMPLE and the samples.txt is opened so the user can select the sample to... (6 Replies)
In the bash function below if the user selets "y" then the menu function is called and if they select "n" the move function is called. That all seems to work, my question is after the files are moved an echo,
line in bold is displayed and another function called backup is called. I am getting a... (1 Reply)
I am sharing a code snippet.
for (( i=0; i<=$(( $count -1 )); i++ ))
do
first=${barr2}
search=${barr1}
echo $first
echo "loop begins"
for (( j=0; j<=5000; j++ ))
do
if } == $search ]]; then
echo $j
break;
fi
done
second=${harr2}
echo $second (2 Replies)
Discussion started by: ngabrani
2 Replies
LEARN ABOUT LINUX
funzip
FUNZIP(1) General Commands Manual FUNZIP(1)NAME
funzip - filter for extracting from a ZIP archive in a pipe
SYNOPSIS
funzip [-password] [input[.zip|.gz]]
ARGUMENTS
[-password]
Optional password to be used if ZIP archive is encrypted. Decryption may not be supported at some sites. See DESCRIPTION for more
details.
[input[.zip|.gz]]
Optional input archive file specification. See DESCRIPTION for details.
DESCRIPTION
funzip without a file argument acts as a filter; that is, it assumes that a ZIP archive (or a gzip'd(1) file) is being piped into standard
input, and it extracts the first member from the archive to stdout. When stdin comes from a tty device, funzip assumes that this cannot be
a stream of (binary) compressed data and shows a short help text, instead. If there is a file argument, then input is read from the speci-
fied file instead of from stdin.
A password for encrypted zip files can be specified on the command line (preceding the file name, if any) by prefixing the password with a
dash. Note that this constitutes a security risk on many systems; currently running processes are often visible via simple commands (e.g.,
ps(1) under Unix), and command-line histories can be read. If the first entry of the zip file is encrypted and no password is specified on
the command line, then the user is prompted for a password and the password is not echoed on the console.
Given the limitation on single-member extraction, funzip is most useful in conjunction with a secondary archiver program such as tar(1).
The following section includes an example illustrating this usage in the case of disk backups to tape.
EXAMPLES
To use funzip to extract the first member file of the archive test.zip and to pipe it into more(1):
funzip test.zip | more
To use funzip to test the first member file of test.zip (any errors will be reported on standard error):
funzip test.zip > /dev/null
To use zip and funzip in place of compress(1) and zcat(1) (or gzip(1) and gzcat(1)) for tape backups:
tar cf - . | zip -7 | dd of=/dev/nrst0 obs=8k
dd if=/dev/nrst0 ibs=8k | funzip | tar xf -
(where, for example, nrst0 is a SCSI tape drive).
BUGS
When piping an encrypted file into more and allowing funzip to prompt for password, the terminal may sometimes be reset to a non-echo mode.
This is apparently due to a race condition between the two programs; funzip changes the terminal mode to non-echo before more reads its
state, and more then ``restores'' the terminal to this mode before exiting. To recover, run funzip on the same file but redirect to
/dev/null rather than piping into more; after prompting again for the password, funzip will reset the terminal properly.
There is presently no way to extract any member but the first from a ZIP archive. This would be useful in the case where a ZIP archive is
included within another archive. In the case where the first member is a directory, funzip simply creates the directory and exits.
The functionality of funzip should be incorporated into unzip itself (future release).
SEE ALSO gzip(1), unzip(1), unzipsfx(1), zip(1), zipcloak(1), zipinfo(1), zipnote(1), zipsplit(1)URL
The Info-ZIP home page is currently at
http://www.info-zip.org/pub/infozip/
or
ftp://ftp.info-zip.org/pub/infozip/ .
AUTHOR
Mark Adler (Info-ZIP)
Info-ZIP 20 April 2009 (v3.95) FUNZIP(1)