07-28-2008
Grep command usage in shell
hi,
I am facing a problem when i use grep command in shell script.
problem is as follows...
1)i has declared an variable (say a)
2)Now i am searching for an pattern in a file and i used the followig command
cat /wls_../../scripts/log.txt | grep $a-JUL-08
i am not getting any output when i run the above command...
can some one please help out in sorting out the problem of how to pass an variable to grep command..
Thanks in advance.
Regards,
hemanth
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ZGREP(1) General Commands Manual ZGREP(1)
NAME
zgrep - search possibly compressed files for a regular expression
SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename...
DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code:
(-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the
standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep.
If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.
EXIT CODE
2 - An option that is not supported was specified.
AUTHOR
Charles Levert (charles@comm.polymtl.ca)
SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)
ZGREP(1)