Sponsored Content
Full Discussion: Print out a selected word.
Top Forums Shell Programming and Scripting Print out a selected word. Post 302217569 by anakiar on Wednesday 23rd of July 2008 04:24:30 AM
Old 07-23-2008
Print out a selected word.

Hi can anyone assist me on my problem.
I try to grep 1 word in 1 line data. Example like below.

* Data below located in a.txt, i just wanna grep just processing-time = "12"

total-octets = "20080718214210Z" total-pages = "" octets-completed = "20080721064351Z" pages-completed = "2" processing-time = "12"


I searched the threat and found 1 solution like below, unfortunately it is just work if the word located in different row not in 1 line row.

sed -ne '/^[ ]*processing-time/s#^\([^=][^=]*\)=\([^/][^/]*\).*#\12#p'

Please assits Smilie thanks.
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

print selected rows with awk

Hi everybody: Could anybody tell me how I can print from a file a selected rows with awk. In my case I only want print in another file all the rows from NR=8 to NR=2459 and the increment each 8 times. I tried to this: awk '{for (i=8; i=2459; i+=8); NR==i}' file1 > file2 But doesn't... (6 Replies)
Discussion started by: tonet
6 Replies

2. Shell Programming and Scripting

print selected lines

Hi everybody: I try to print in new file selected lines from another file wich depends on the first column. I have done a script like this: lines=( "1" "2" "3" "4" "5" "6" "7" "8" "9" "10" "11" "21" "31" "41" "51" "55" "57" "58" ) ${lines} for lines in ${lines} do awk -v ... (6 Replies)
Discussion started by: tonet
6 Replies

3. UNIX for Dummies Questions & Answers

How to print selected pages

I have a large file and want to print out, but I don't want to print all, just some pages. Like if the file has 100 pages, I just want to print out page 3-34 and 67-87. How can I do? By the way, I already try "lp -o page-ranges=value" command which doesn't work on my computer because -o <option>... (2 Replies)
Discussion started by: wendyz
2 Replies

4. Shell Programming and Scripting

Need to print only selected char in a string..?

Hi, I want to print particular chars in a string. for example ie., consider " dear,. roopa$#09%~`';']" as the example string. Here, I want to print only alphanumeric chars.. suppose , if i want only alphanumeric... value would be "dear roopa09" suppose , if i want some spl char(,) with... (2 Replies)
Discussion started by: balan_mca
2 Replies

5. Shell Programming and Scripting

trying to print selected fields of selected lines by AWK

I am trying to print 1st, 2nd, 13th and 14th fields of a file of line numbers from 29 to 10029. I dont know how to put this in one code. Currently I am removing the selected lines by awk 'NR==29,NR==10029' File1 > File2 and then doing awk '{print $1, $2, $13, $14}' File2 > File3 Can... (3 Replies)
Discussion started by: ananyob
3 Replies

6. UNIX for Dummies Questions & Answers

Script to search for a particular word in files and print the word and path name

Hi, i am new to unix shell scripting and i need a script which would search for a particular word in all the files present in a directory. The output should have the word and file path name. For example: "word" "path name". Thanks for the reply in adv,:) (3 Replies)
Discussion started by: virtual_45
3 Replies

7. Shell Programming and Scripting

Print selected lines from file in order

I need to extract selected lines from a log file, I can use grep to pull one line matching 'x' or matching 'y', how can I run through the log printing both matching lines in order top to bottom. i.e line 1 xyz - not needed line 2 User01 - needed line 3 123 - not needed line 4 Info - needed... (2 Replies)
Discussion started by: rosslm
2 Replies

8. Shell Programming and Scripting

only print a selected row

this works: cat file.txt| awk 'NR==45,NR==55' but how do I assign variables instead of numbers: this does not work: cat file.txt | awk 'NR==$start,NR==$end' there need variables instead of numbers Sorry for my English Thank you for answer (3 Replies)
Discussion started by: gizmo16
3 Replies

9. Shell Programming and Scripting

How to print selected fields

HI, I am using below command to display the words, but i am getting awk error. Please help me out on this I am using below code i am getting error as If i use below code i am getting below OP Output from where i am trying to select the fields after delimiter "," from here i want to... (5 Replies)
Discussion started by: darling
5 Replies

10. Shell Programming and Scripting

Search for a specific word and print only the word from the input file

Hi, I have a sample file as shown below, I am looking for sed or any command which prints the complete word only from the input file. Ex: $ cat "sample.log" I am searching for a word which is present in this file We can do a pattern search using grep but I need to cut only the word which... (1 Reply)
Discussion started by: mohan_kumarcs
1 Replies
SHELL-QUOTE(1)						User Contributed Perl Documentation					    SHELL-QUOTE(1)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.16.3 2010-06-11 SHELL-QUOTE(1)
All times are GMT -4. The time now is 05:34 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy