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Top Forums Shell Programming and Scripting how to get line number of different words if exists in same line Post 302216775 by fpmurphy on Monday 21st of July 2008 06:38:10 AM
Old 07-21-2008
Assuming that the pattern is "Date Sex Address" and not any combination thereof
Code:
$ sed -n '/Date Sex Address/=' file
5

 

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Date::Manip::Changes6(3)				User Contributed Perl Documentation				  Date::Manip::Changes6(3)

NAME
Date::Manip::Changes6 - backward incompatible changes in Date::Manip 6.xx SYNOPSIS
This describes all backwards incompatible changes made to the Date::Manip module starting at version 6.00. DESCRIPTION
For the most part, Date::Manip has remained backward compatible at every release, but occasionally, a change is made which is backward incompatible. These are documented here. Major changes are marked with asterisks. 6.05 %z format In Date::Manip 5.xx, the %z format in UnixDate printed the offset in the form -0500. In 6.00, I changed that to -05:00:00, but this broke RFC 822 compliance. I've changed %z back to -0500, and introduced a new format (%N) which returns -05:00:00. Incidentally, this is the LAST unused letter, so I am now going to have to either stop adding formats, or add some extended format syntax. Not sure yet which, but this may involve a backwards incompatible change in the future. BUGS AND QUESTIONS
Please refer to the Date::Manip::Problems documentation for information on submitting bug reports or questions to the author. SEE ALSO
Date::Manip - main module documentation LICENSE
This script is free software; you can redistribute it and/or modify it under the same terms as Perl itself. AUTHOR
Sullivan Beck (sbeck@cpan.org) perl v5.12.1 2010-01-12 Date::Manip::Changes6(3)
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