07-18-2008
I'm also looking for a shell script that will return the previous Saturday's date from any given date.
Tried to look everywhere but cannot find any solution. I don't want to use the existing datecalc function.
Thank you.
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LEARN ABOUT PHP
date_parse_from_format
DATE_PARSE_FROM_FORMAT(3) 1 DATE_PARSE_FROM_FORMAT(3)
date_parse_from_format - Get info about given date formatted according to the specified format
SYNOPSIS
array date_parse_from_format (string $format, string $date)
DESCRIPTION
Returns associative array with detailed info about given date.
PARAMETERS
o $format
- Format accepted by DateTime.createFromFormat(3).
o $date
- String representing the date.
RETURN VALUES
Returns associative array with detailed info about given date.
EXAMPLES
Example #1
date_parse_from_format(3) example
<?php
$date = "6.1.2009 13:00+01:00";
print_r(date_parse_from_format("j.n.Y H:iP", $date));
?>
The above example will output:
Array
(
[year] => 2009
[month] => 1
[day] => 6
[hour] => 13
[minute] => 0
[second] => 0
[fraction] =>
[warning_count] => 0
[warnings] => Array
(
)
[error_count] => 0
[errors] => Array
(
)
[is_localtime] => 1
[zone_type] => 1
[zone] => -60
[is_dst] =>
)
SEE ALSO
DateTime.createFromFormat(3), checkdate(3).
PHP Documentation Group DATE_PARSE_FROM_FORMAT(3)