hey guys, how do i replace only a line within a file without messing up the rest of the contents of the file?
see, if possible can you guys give me a straight forward way to do this. i dont want a complex command. what i mean is i know i can accomplish this by using sed, well, i think i can,... (3 Replies)
Hi,
Apologies if this has been asked before, but I searched and was not able to find an answer. It's probably a simple question to answer for those of you with some experience, though...
I have a relatively long string where tokens are separated by the colon (':') character. Let's say the... (10 Replies)
Hi All
I have a requirement where using a script I grep a file for string (KSG/Password in below ) , get the next line which is the password and I need replace the whole line of unknown special charecters (encrypted password) with another line as given below .
As in below i need to get... (12 Replies)
Hi Masters ,
I have a file whose header is like
HDRCZECM8CZCM000000881 SVR00120100401160828+020020100401160828+0200CZK
There is a space between 1 and S ,my req is to chng the space to T
I tried echo `head -1 CDCZECM8CZCM000000881` | sed 's/ /T/'
it works ,but how can I modify in... (5 Replies)
Hi All,
I have a set of files named S5_SK1.chr01 S5_SK1.chr02 S5_SK1.chr03 ..... and the first line of these files is >SK1.chr01 >SK1.chr02 >SK1.chr03 ..... Can anyone suggest how I can change the first line of all these files with the filename itself? So my expected output for the first lines of... (14 Replies)
Hi All,
As mentioned in the title I have two text files and I would like to replace line number 5 of file #1 with line number 4 of file #2
e.g.
file 1
wqwert
4.4464002
3
319
286
369
46.320002
56.150002
45.100002
1
1
1
0.723 (12 Replies)
I have a file which has a list in it
pop
triangle
people
slow
fast
What I want to do is search this list and replace people with humans do the list looks like this:
pop
triangle
human
slow
fast
I think i use something like this....
if cat /list.txt | grep -q 'people' ; then (9 Replies)
Hi all,
I need to replace a line
export TZ=xxxxxxxx
with the line
export TZ=$1
Now, "xxxxxxxx" in the above line is some unknown string and $1 is a parameter. I want the content of $1 to be replaced with "xxxxxxxx".
Kindly help me how to do this in the shell scripting. (5 Replies)
Hi Guys,
I am having a set of date format files files where I am performing the below set of operations in the files . I Need to replace the last line value with specific date which is a pipe delimited file.
for egf1_20140101.txt
aa|aus|20140101|yy
bb|nz|20140101|yy
.
.... (19 Replies)
Discussion started by: rohit_shinez
19 Replies
LEARN ABOUT SUSE
root
ROOT(1) General Commands Manual ROOT(1)NAME
root - Interpretor of C++ for the ROOT framework
SYNOPSIS
root [options] files ...
DESCRIPTION
ROOTs Object-Oriented Technologies.
root is a interactive interpretor of C++ code. It uses the ROOT framework. For more information on ROOT, please refer to
http://root.cern.ch.
An extensive Users Guide is available from that site.
OPTIONS
-? Show summary of options.
-b Run in batch mode without graphics
-n Do not execute logon and logoff macros as specified in .rootrc
-q Exit after processing command line macro files
-l Do not show splash screen
SEE ALSO rootcint(1), cint(1), root-config(1), rootd(1), h2root(1), g2root(1)
For extensive documentation on the ROOT system, see http://root.cern.ch <http://root.cern.ch>
A Users Guide is available online. <http://root.cern.ch/root/UsersGuide.html>
The classes of ROOT are all documented by the automatic documentation system, and is available online.
<http://root.cern.ch/root/html/ClassIndex.html>
FILES
<etcdir>/system.rootrc
System-wide configuration file. <etcdir> either ROOTSYS, or something like /etc/root
<libdir>/*
ROOT C++ class libraries. <libdir> is either ROOTSYS/lib or something like /usr/lib/root.
<incdir>/*
The header files for the ROOT C++ class libraries. <incdir> is either ROOTSYS/include or something like /usr/include/root.
~/.rootrc, ./.rootrc
User configuration file
ORIGINAL AUTHORS
The ROOT team (see web page above):
Rene Brun and Fons Rademakers
COPYRIGHT
This library is free software; you can redistribute it and/or modify it under the terms of the GNU Lesser General Public License as pub-
lished by the Free Software Foundation; either version 2.1 of the License, or (at your option) any later version.
This library is distributed in the hope that it will be useful, but WITHOUT ANY WARRANTY; without even the implied warranty of MER-
CHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU Lesser General Public License for more details.
You should have received a copy of the GNU Lesser General Public License along with this library; if not, write to the Free Software Foun-
dation, Inc., 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA
AUTHOR
This manual page was written by Christian Holm Christensen <cholm@nbi.dk>, for the Debian GNU/Linux system (but may be used by others).
ROOT Version 3 ROOT(1)