06-04-2008
You can try using sudo with the eject command , without password.sudo works like a charm!
10 More Discussions You Might Find Interesting
1. UNIX for Dummies Questions & Answers
hi,
my problem is that i am calling a script from my perl program.
the script checks wether a particular process is running or not if the process is not running then it should start the process.
the problem here is that the front end logs into backend with a user which does not have the... (0 Replies)
Discussion started by: raviraushanjha
0 Replies
2. Shell Programming and Scripting
Good day Guys!!!
I am currently making a script in AIX, the script runs a SAS job, the owner of the script is the root, but the SAS jobs cannot be run by the root, as it should be run by a user 'sasia'. But inside the script, root creates a logfile, so what I need is just to su to sasia for the... (3 Replies)
Discussion started by: sasia
3 Replies
3. AIX
I'm trying to give a non-root user the right to start IBM HTTP Server, the web server is listening on port 80, but for AIX, ports under 1024 are privilege ports which can be used only by root.
/usr/IBMIHS/bin# ./apachectl start
(13)Permission denied: make_sock: could not bind to address :::80... (1 Reply)
Discussion started by: ibmer414
1 Replies
4. Solaris
Hi Friends,
I am new to Sun solaris unix.I am facing problem while runing my kornshell script just as an ordinary user.The script works fine while i am working as a super user.the script just uses awk to check the first charcter of a file and then copies the file to another folder. Do i... (4 Replies)
Discussion started by: gjithin
4 Replies
5. Shell Programming and Scripting
hi friends,
I am a new Sun Solaris 10 user. I have the following script
line=$(awk '{if(substr($0,1,1)!="#" &&
substr($0,1,1)!=";" &&
substr($0,1,1)!=" " &&
substr($0,1,1)!="/" &&
substr($0,1,1)!="*" &&
substr($0,1,1)!="\\" &&
length($0)!=0)
... (10 Replies)
Discussion started by: gjithin
10 Replies
6. Linux
Hi,
Is it possible to grant root privileges to an ordinary user?
Other than 'sudo', is there some way under Users/Groups configuration?
I want ordinary user to be able to mount, umount and use command mt.
/Brendan (4 Replies)
Discussion started by: brendan76
4 Replies
7. UNIX for Dummies Questions & Answers
How to give an ordinary user the superuser (root) ID which is 0 (9 Replies)
Discussion started by: sharaola
9 Replies
8. Shell Programming and Scripting
Hi All
I have written one shell script for GPRS route add is given below named GPRSRouteSet.sh
URL="www.google.com"
VBURL="10.5.2.211"
echo "Setting route for $URL for GPRS"
URL_Address=`nslookup $URL|grep Address:|grep -v "#"|awk -F " " '{print $2}'|head -1`
echo "Executing ... (3 Replies)
Discussion started by: mnmonu
3 Replies
9. Shell Programming and Scripting
Hi Experts,
I had tried to executes this script to change the user password through script:
No lines in buffer
#!/bin/ksh
cat /etc/passwd | grep -v userid >> /tmp/pass.tmp1
cat /etc/passwd | grep userid >> /tmp/pass.tmp2
PASS1=`cat /tmp/pass.tmp2 | cut -d ":" -f2`
PASS2=`q2w3e4r5`
sed... (3 Replies)
Discussion started by: indrajit_renu
3 Replies
10. UNIX for Dummies Questions & Answers
Hi,
I want to change the password of unix users on a number of servers.My plan was to ssh to all the servers in a shell script and use the passwd command. I tried to do so but everytime i run it i get this error.
ssh -x -n -l user1 host passwd
Changing password for "user1"
3004-709 Error... (3 Replies)
Discussion started by: poojabhat
3 Replies
LEARN ABOUT MOJAVE
heimdal_debug
heimdal_debug(5) BSD File Formats Manual heimdal_debug(5)
NAME
heimdal_debug -- how to turn on/off debugging for Kerberos tools
DESCRIPTION
The heimdal_debug kerberos frameworks have several knobs for controlling logging. The different framework knobs are:
libkrb
The Kerberos library, some gss-api Kerberos output ends up here too
kcm the kcm library (credentials cache, ntlm client)
kdc the kerberos KDC output
digest-service
the digest service (ntlm server)
CONFIGURATION FILE
[logging]
<subsystem> = 0-/SYSLOG:
and watch syslog for logging information.
APPLE MAC OS X
First turn up syslog debugging
sudo syslog -c 0 -d
then you can see the syslog output in Console.app or by running
syslog -w -k org.h5l.asl
To enable more extensive debugging logging for each subsystem, use the following commands:
Kerberos Library
sudo defaults write /Library/Preferences/com.apple.Kerberos logging -dict-add krb5 '0-/OSLOG:normal:'
digest-server
sudo defaults write /Library/Preferences/com.apple.Kerberos logging -dict-add digest-service '0-/OSLOG:normal:'
kcm sudo defaults write /Library/Preferences/com.apple.Kerberos logging -dict-add kcm '0-/OSLOG:normal:'
kdc sudo defaults write /Library/Preferences/com.apple.Kerberos logging -dict-add kdc '0-/OSLOG:normal:'
MIT Kerberos Shim
defaults write com.apple.MITKerberosShim EnableDebugging -bool true
GSS-API framework logging
sudo defaults write /Library/Preferences/com.apple.GSS DebugLevel -int 10
Other options on Mac OS X
Make the admin API pretend to the server even on client
sudo defaults write /Library/Preferences/com.apple.Kerberos ForceHeimODServerMode -bool true
SEE ALSO
gss(5), kerberos(8)
HEIMDAL
Sep 30, 2011 HEIMDAL