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Full Discussion: ! operator in variable
Top Forums Shell Programming and Scripting ! operator in variable Post 302200769 by mmunir on Friday 30th of May 2008 03:21:29 AM
Old 05-30-2008
! operator in variable

Can any body kindly tell me the purpose of ! operator in the following expression:

y=${!x}

Actually when i execute this statement on my solaris 10 terminal, i get empty output.
 

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DROP OPERATOR 
CLASS(7) SQL Commands DROP OPERATOR CLASS(7) NAME
DROP OPERATOR CLASS - remove a user-defined operator class SYNOPSIS
DROP OPERATOR CLASS name USING access_method [ CASCADE | RESTRICT ] INPUTS name The name (optionally schema-qualified) of an existing operator class. access_method The name of the index access method the operator class is for. CASCADE Automatically drop objects that depend on the operator class. RESTRICT Refuse to drop the operator class if there are any dependent objects. This is the default. OUTPUTS DROP OPERATOR CLASS The message returned if the command is successful. DESCRIPTION
DROP OPERATOR CLASS drops an existing operator class from the database. To execute this command you must be the owner of the operator class. NOTES The DROP OPERATOR CLASS statement is a PostgreSQL language extension. Refer to CREATE OPERATOR CLASS [create_operator_class(7)] for information on how to create operator classes. USAGE
Remove B-tree operator class widget_ops: DROP OPERATOR CLASS widget_ops USING btree; This command will not execute if there are any existing indexes that use the operator class. Add CASCADE to drop such indexes along with the operator class. COMPATIBILITY
SQL92 There is no DROP OPERATOR CLASS in SQL92. SQL - Language Statements 2002-11-22 DROP OPERATOR CLASS(7)
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