05-21-2008
date command in AIX
hi,
i have a simple question
in linux:
date '+%s' -r filename--------> gives the file age in seconds
i want the option to be used with date command in AIX ??
10 More Discussions You Might Find Interesting
1. Shell Programming and Scripting
I want to get previous date from date command. I am using ksh shell.
Exmp:
today is 2008.09.04
I want the result : 2008.09.03
Please help.
Thanks in advance. (4 Replies)
Discussion started by: rinku
4 Replies
2. AIX
Hello everybody,
plz tell me the command for chaging the date paramater in IBM AIX.. (3 Replies)
Discussion started by: oracle_rajesh_k
3 Replies
3. AIX
When I import VG, it shows:
0516-622 synclvodm: Warning, cannot write lv control block data.
I found AIX V4.3 have updatelv command can recovery LVB from VG, however, updatelv is not existed on AIX 5L, which command to replace it? (2 Replies)
Discussion started by: rainbow_bean
2 Replies
4. Shell Programming and Scripting
Hi,
does anybody know how to format `date` command correctly to return the day of the week? Thanks -A
I work in ksh.... (1 Reply)
Discussion started by: aoussenko
1 Replies
5. AIX
How could we derive teh Next month in MON-RR format from current date ie sysdate in UNI AIX sheel script.I coould get a command but i supports only inLinux susse andnotin AIX.
I need for Unix AIX.Pls Help.
Regards
Shiv (2 Replies)
Discussion started by: SHIV75
2 Replies
6. Shell Programming and Scripting
Hi
I want to get tomorrow and yesterday date from date command. My shell is KSH and server is AIX. I tried several options, but unable to do. Please help on this.
Regards
Rajesh (5 Replies)
Discussion started by: rajeshmepco
5 Replies
7. Shell Programming and Scripting
Hi,
I am trying to find an option in unix to increment for date filed.
I tried in the unix forums. unable to find the direct command to increment the value.
code
a= 01/Apr/13
while
do
echo $a
a=`expr $a + 1`
done
example
Input:
a= 01/Apr/13
Output:
01/Apr/13
02/Apr/13... (15 Replies)
Discussion started by: onesuri
15 Replies
8. Shell Programming and Scripting
Hi all,
Need an urgent help on the below scenario.
script:
awk -F","
'BEGIN { #some variable assignment}
{ #some calculation and put values in array}
END {
year=#getting it from array and assume this will be 2014
month=#getting it from array and this will be 05
date=#... (7 Replies)
Discussion started by: vijaidhas
7 Replies
9. HP-UX
HI,
Can anyone tell me how to pull the date and file name separated by a space using the find command or any other command. I want to look through several directories and based on a date timeframe (find -mtime -7), output the file name (without the path) and the date(in format mmddyyyy) to a... (2 Replies)
Discussion started by: lnemitz
2 Replies
10. HP-UX
current date command runs well
awk -v t="$(date +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
subtract 30 days fails
awk -v t="$(date --date="-30days" +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
awk command in hp unix subtract 30 days automatically from current date without date illegal option error... (20 Replies)
Discussion started by: kmarcus
20 Replies
LEARN ABOUT PHP
datetime.sub
DATETIME.SUB(3) 1 DATETIME.SUB(3)
DateTime::sub - Subtracts an amount of days, months, years, hours, minutes and seconds from a DateTime object
Object oriented style
SYNOPSIS
public DateTime DateTime::sub (DateInterval $interval)
DESCRIPTION
Procedural style
DateTime date_sub (DateTime $object, DateInterval $interval)
Subtracts the specified DateInterval object from the specified DateTime object.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $interval
- A DateInterval object
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
EXAMPLES
Example #1
DateTime.sub(3) example
Object oriented style
<?php
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('P10D'));
echo $date->format('Y-m-d') . "
";
?>
Procedural style
<?php
$date = date_create('2000-01-20');
date_sub($date, date_interval_create_from_date_string('10 days'));
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2000-01-10
Example #2
Further DateTime.sub(3) examples
<?php
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('PT10H30S'));
echo $date->format('Y-m-d H:i:s') . "
";
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('P7Y5M4DT4H3M2S'));
echo $date->format('Y-m-d H:i:s') . "
";
?>
The above example will output:
2000-01-19 13:59:30
1992-08-15 19:56:58
Example #3
Beware when subtracting months
<?php
$date = new DateTime('2001-04-30');
$interval = new DateInterval('P1M');
$date->sub($interval);
echo $date->format('Y-m-d') . "
";
$date->sub($interval);
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-03-30
2001-03-02
NOTES
DateTime.modify(3) is an alternative when using PHP 5.2.
SEE ALSO
DateTime.add(3), DateTime.diff(3), DateTime.modify(3).
PHP Documentation Group DATETIME.SUB(3)