Sponsored Content
Full Discussion: substr not working
Top Forums Shell Programming and Scripting substr not working Post 302193760 by pukars4u on Sunday 11th of May 2008 12:41:05 AM
Old 05-11-2008
substr not working

Hi I am trying to run this command in ksh ...its not working

$line="123356572867116w1671716"
actual_length = 16
cut_line=`awk 'BEGIN{print substr(ARGV[1],1,actual_length)}' "$line"`
the substr is not giving me an output

how can i make it done
can anyone hwlp me on this

cut_line=`awk 'BEGIN{print substr(ARGV[1],1,16)}' "$line"`

This is working ...But I want variable to be passed instead of numeric
please guide me

Thanks,
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

awk substr?

Sorry if this has been posted before, I searched but not sure what I really want to do. I have a file with records that show who has logged into my application: 2003-03-14:I:root: Log_mesg: registered servername:userid. (more after this) I want to pull out the userid, date and time into... (2 Replies)
Discussion started by: MizzGail
2 Replies

2. Shell Programming and Scripting

Substr of variable

Dear All, I am new to Unix and need your help. I am trying to write b-shell script which will return substr of some variable like this d="asdfg" return Substr(d,1,5). Please help (5 Replies)
Discussion started by: giviut
5 Replies

3. Shell Programming and Scripting

Using substr

What is the more efficient way to do this (awk only and default FS) ? $ echo "jefe@alm"|awk '{pos = index($0, "@");printf ("USER: %s\n",substr ($0,1,pos-1))}' USER: jefe Thx in advance (2 Replies)
Discussion started by: Klashxx
2 Replies

4. UNIX for Dummies Questions & Answers

Substr

Hi, My input file is 41;2;xxxx;yyyyy.... 41;2;xxxx;yyyyy.... 41;2;xxxx;yyyyy.... .. .. I need to change the second field value from 2 to 1. i.e., 41;1;xxxx;yyyyy.... 41;1;xxxx;yyyyy.... 41;1;xxxx;yyyyy.... .. .. Thanks in advance. (9 Replies)
Discussion started by: deepakwins
9 Replies

5. Shell Programming and Scripting

get substr?

Hi, I have a long string like, aabab|bcbcbcbbc|defgh|paswd123 dedededede|efef|ghijklmn|paswd234 ghghghghgh|ijijii|klllkkk|paswd345 lmlmlmmm|nononononn|opopopopp|paswd456 This string is devided into one space between substrings. This substrings are, aabab|bcbcbcbbc|defgh|paswd123... (6 Replies)
Discussion started by: syamkp
6 Replies

6. UNIX for Dummies Questions & Answers

substr of a file

.wysiwyg { PADDING-RIGHT: 0px; PADDING-LEFT: 0px; BACKGROUND: #f5f5ff; PADDING-BOTTOM: 0px; MARGIN: 5px 10px 10px; FONT: 10pt verdana, geneva, lucida, 'lucida grande', arial, helvetica, sans-serif; COLOR: #000000; PADDING-TOP: 0px } .wysiwyg A:link { COLOR: #22229c } .wysiwyg_alink { COLOR:... (1 Reply)
Discussion started by: davyp74
1 Replies

7. UNIX for Dummies Questions & Answers

substr

can anybody explain this code? thanks in advance..:) (6 Replies)
Discussion started by: janani_kalyan
6 Replies

8. Shell Programming and Scripting

awk substr

Hello life savers!! Is there any way to use substr in awk command for returning one part of a string from declared start and stop point? I mean I know we have this: substr(string, start, length) Do we have anything like possible to use in awk ? : substr(string, start, stop) ... (9 Replies)
Discussion started by: @man
9 Replies

9. Shell Programming and Scripting

How to use if/else if with substr?

I have a command like this: listdb ID923 -l |gawk '{if (substr($0,37,1)==1 && NR == 3)print "YES" else if (substr ($0,37,1)==0 && NR == 3) print "NO"}' This syntax doesn't work. But I was able to get this to work: listdb ID923 -l |gawk '{if (substr($0,37,1)==1 && NR == 3)print "YES"}' ... (4 Replies)
Discussion started by: newbie2010
4 Replies

10. UNIX for Dummies Questions & Answers

Substr

awk '/^>/{id=$0;next}length>=7 { print id, "\n"$0}' Test.txt Can I use substr to achieve the same task? Thanks! (8 Replies)
Discussion started by: Xterra
8 Replies
USB_BULK_MSG(9) 						   USB Core APIs						   USB_BULK_MSG(9)

NAME
usb_bulk_msg - Builds a bulk urb, sends it off and waits for completion SYNOPSIS
int usb_bulk_msg(struct usb_device * usb_dev, unsigned int pipe, void * data, int len, int * actual_length, int timeout); ARGUMENTS
usb_dev pointer to the usb device to send the message to pipe endpoint "pipe" to send the message to data pointer to the data to send len length in bytes of the data to send actual_length pointer to a location to put the actual length transferred in bytes timeout time in msecs to wait for the message to complete before timing out (if 0 the wait is forever) CONTEXT
!in_interrupt () DESCRIPTION
This function sends a simple bulk message to a specified endpoint and waits for the message to complete, or timeout. If successful, it returns 0, otherwise a negative error number. The number of actual bytes transferred will be stored in the actual_length paramater. Don't use this function from within an interrupt context, like a bottom half handler. If you need an asynchronous message, or need to send a message from within interrupt context, use usb_submit_urb If a thread in your driver uses this call, make sure your disconnect method can wait for it to complete. Since you don't have a handle on the URB used, you can't cancel the request. Because there is no usb_interrupt_msg and no USBDEVFS_INTERRUPT ioctl, users are forced to abuse this routine by using it to submit URBs for interrupt endpoints. We will take the liberty of creating an interrupt URB (with the default interval) if the target is an interrupt endpoint. COPYRIGHT
Kernel Hackers Manual 2.6. July 2010 USB_BULK_MSG(9)
All times are GMT -4. The time now is 03:03 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy