hello,
I am trying to parse an error returned by a command inside the if statement but it is just displays the full error instead and then stops.
if ; then
echo "no such package"
else
echo "similar version found will use pkgrm"
fi
the above code just displays
please let me know... (2 Replies)
:b:hi,
I have a script as given below:
pr_det="1"
if
then
awk ' BEGIN {printf("%23s","session")}' >> report.txt
awk ' BEGIN {printf "\n"} ' >> report.txt
else
awk ' BEGIN {printf("%55s","file_dsc")} ' >> report.txt
awk ' BEGIN {printf("%101s","no_recs")} '... (1 Reply)
year=`date '+%Y'`
month=`date '+%m'`
day=`date '+%d'`
day=`expr $day - 1`
case $month in
1 | 3 | 5 | 7 | 8 | 10 | 12);;
if($day =7 ); then
$day=6
fi
4 | 6 | 9 | 11);;
if ; then
$day=31
fi
2);;
if ; then
if ; then (2 Replies)
HI i am getting error while executing the given statement
for filename in `cat a/file.lst`
do
if then
echo "Exit Code Description :File $filename - is missing in Input Directory" >a.log
exit
else
count1=`awk 'END {print NR}' $filename`
echo "$count1">>a.log
count2=`awk 'END {print... (4 Replies)
hi,
When i try to run the code below, i get the following error
"ksh: syntax error: `(' unexpected"
i am not able to figure it out. Can anyone help me?
Code: (2 Replies)
Hi,
This is my script to catch any oracle errors.
In this, the $sqlerr returns
ORA-01017: invalid username/password; logon denied
when i specify wrong username/password
the if condition is failing. how can i resolve the issue.
the if statement gives error
sqloutput=`sqlplus -s -L... (1 Reply)
Hi
Can you please tell me what is wrong with this line:
if && ]; then
basically i want to check if x = 12 and F (Filename) end with 'g'. But it is throwing syntax error. (7 Replies)
Can anybody tell the correct way to use the following awk pattern check within an if statement?
When I run this command outside of the if statement
cat /tmp/test2.out | awk -v T=$TIME -v G=$GROUP -v C=$CDATE '$0 ~ T && $0 ~ G && $0 ~ C' | grep -i "Starting the group"
I get the following... (0 Replies)
hello all
im new to unix and when i use below script i get an error :
#! /bin/bash
Echo -e "enter the name of the file : \c"
read file_name
if
then
echo "$file_name found"
else
echo "$file_name not found"
fi
running the script i get below error :
$ ./hello (26 Replies)
Discussion started by: Ibrahims1
26 Replies
LEARN ABOUT PHP
sqlsrv_free_stmt
SQLSRV_FREE_STMT(3)SQLSRV_FREE_STMT(3)sqlsrv_free_stmt - Frees all resources for the specified statementSYNOPSIS
bool sqlsrv_free_stmt (resource $stmt)
DESCRIPTION
Frees all resources for the specified statement. The statement cannot be used after sqlsrv_free_stmt(3) has been called on it. If sql-
srv_free_stmt(3) is called on an in-progress statement that alters server state, statement execution is terminated and the statement is
rolled back.
PARAMETERS
o $stmt
- The statment for which resources are freed. Note that NULL is a valid parameter value. This allows the function to be called
multiple times in a script.
RETURN VALUES
Returns TRUE on success or FALSE on failure.
EXAMPLES
Example #1
sqlsrv_free_stmt(3) example
<?php
$serverName = "serverNamesqlexpress";
$connectionInfo = array( "Database"=>"dbName", "UID"=>"username", "PWD"=>"password");
$conn = sqlsrv_connect( $serverName, $connectionInfo);
if( $conn === false ) {
die( print_r( sqlsrv_errors(), true));
}
$stmt = sqlsrv_query( $conn, "SELECT * FROM Table_1");
if( $stmt === false ) {
die( print_r( sqlsrv_errors(), true));
}
/*-------------------------------
Process query results here.
-------------------------------*/
/* Free the statement resources. */
sqlsrv_free_stmt( $stmt);
?>
NOTES
The main difference between sqlsrv_free_stmt(3) and sqlsrv_cancel(3) is that a statement resource cancelled with sqlsrv_cancel(3) can be
re-executed if it was created with sqlsrv_prepare(3). A statement resource cancelled with sqlsrv_free_statement(3) cannot be re-executed.
SEE ALSO sqlsrv_cancel(3).
PHP Documentation Group SQLSRV_FREE_STMT(3)