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Top Forums UNIX for Dummies Questions & Answers Executing file without excute permission. Post 302193039 by Zarnick on Thursday 8th of May 2008 10:32:41 AM
Old 05-08-2008
Just to complement andryk answer, if you want to execute it as ./test.sh, you should put the executable flag in it, and you shell script should begin with the line:
Code:
#!/bin/sh

And here's to put the executable flag
Code:
chmod u+x test.sh

 

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CHMOD(1)						      General Commands Manual							  CHMOD(1)

NAME
chmod - change mode SYNOPSIS
chmod mode file ... DESCRIPTION
The mode of each named file is changed according to mode, which may be an octal number or a symbolic change to the existing mode. A mode is an octal number constructed from the OR of the following modes. 0400 read by owner 0200 write by owner 0100 execute (search in directory) by owner 0070 read, write, execute (search) by group 0007 read, write, execute (search) by others A symbolic mode has the form: [who] op permission The who part is a combination of the letters u (for user's permissions), g (group) and o (other). The letter a stands for ugo. If who is omitted, the default is a. Op can be + to add permission to the file's mode, - to take away permission, and = to assign permission absolutely (all other bits will be reset). Permission is any combination of the letters r (read), w (write), x (execute), a (append only), and l (exclusive access). Only the owner of a file or the group leader of its group may change the file's mode. SOURCE
/sys/src/cmd/chmod.c SEE ALSO
ls(1), stat(2), stat(5) CHMOD(1)
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