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Top Forums Shell Programming and Scripting Snytax error on If Statement--help Post 302192798 by dannyd_y on Wednesday 7th of May 2008 10:47:15 PM
Old 05-07-2008
Ok i've fixed

year=`date '+%Y'`
month=`date '+%m'`
day=`date '+%d'`
day=`expr $day - 1`

case $month in
1 | 3 | 5 | 7 | 8 | 10 | 12)
if [ $day = 7 ]
then
$day=6
fi
;;

4 | 6 | 9 | 11)
if [ $day = 0 ]
then
$day=31
fi
;;

2)
if [ $day = 0 ]
then
if [ `expr $year % 4` -eq 0]
then
$day = 28
else
$day = 29
fi
fi
;;
*) echo error: Case Statement Not Run ;;
esac

DATE=$year$month$day
cp $HOME/*$DATE*log $HOME/QVGLog
cd $HOME/QVGLog
gzip *


now the problem is the case statement failed, the message is
error: Case Statement Not Run
cp: cannot stat `/sgxde/sgxaspecs7/*2008057*log': No such file or directory
gzip: *: No such file or directory


Smilie
 

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DATETIME.SETDATE(3)							 1						       DATETIME.SETDATE(3)

DateTime::setDate - Sets the date

       Object oriented style

SYNOPSIS
public DateTime DateTime::setDate (int $year, int $month, int $day) DESCRIPTION
Procedural style DateTime date_date_set (DateTime $object, int $year, int $month, int $day) Resets the current date of the DateTime object to a different date. PARAMETERS
o $object -Procedural style only: A DateTime object returned by date_create(3). The function modifies this object. o $year - Year of the date. o $month - Month of the date. o $day - Day of the date. RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure. CHANGELOG
+--------+---------------------------------------------------+ |Version | | | | | | | Description | | | | +--------+---------------------------------------------------+ | 5.3.0 | | | | | | | Changed the return value on success from NULL to | | | DateTime. | | | | +--------+---------------------------------------------------+ EXAMPLES
Example #1 DateTime.setDate(3) example Object oriented style <?php $date = new DateTime(); $date->setDate(2001, 2, 3); echo $date->format('Y-m-d'); ?> Procedural style <?php $date = date_create(); date_date_set($date, 2001, 2, 3); echo date_format($date, 'Y-m-d'); ?> The above examples will output: 2001-02-03 Example #2 Values exceeding ranges are added to their parent values <?php $date = new DateTime(); $date->setDate(2001, 2, 28); echo $date->format('Y-m-d') . " "; $date->setDate(2001, 2, 29); echo $date->format('Y-m-d') . " "; $date->setDate(2001, 14, 3); echo $date->format('Y-m-d') . " "; ?> The above example will output: 2001-02-28 2001-03-01 2002-02-03 SEE ALSO
DateTime.setISODate(3), DateTime.setTime(3). PHP Documentation Group DATETIME.SETDATE(3)
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